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Alex
3 years ago
7

Four scales of measurement are: nominal, ordinal, interval, and ratio.

Mathematics
1 answer:
RideAnS [48]3 years ago
8 0

Answer:

The answer are (a) measurement on ordinary scale can be ranked, but on nominal scale observation cannot be ranked, (b)  on the interval scale measurement can be compared in terms of difference of magnitude, but on ordinary scale, observations cannot be compared in terms of magnitude (c) the point of zero is arbitrary and can be found in any where on the measurement of interval scale

Step-by-step explanation:

Explanation

(a) In nominal scale measurement, observations are classified but in ordinal scale measurement  observations are ranked

Therefore additional information of comparing ranking in observation when measurement are gotten from ordinary scale as compared to nominal measurement.

(b) In interval scale measurement  can be compared by different magnitude  because it is ranked, while ordinary scale measurement, observation can be ranked for comparison

For example the grade of student in a school are grouped under the ordinary scale of measurement due to the fact that Grade A is greater than B

Therefore we have extra information of contrasting observations based on magnitude differences when measurement are gotten form interval scale  as against  ordinary scale

(c) In the interval scale of measurement,  observations are compared in terms of magnitude differences. the point of zero is arbitrary and can found anywhere

For example if a person has no salary what this means is that he has rupes of zero (salary)

Then again, the additional information of the zero point of arbitrary is when measurement is gotten from interval scale. what this suggest is that none is in the scale of ratio

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Solve(x+y)^2=(x^2-2xy+y^2) and show your work
Shtirlitz [24]

(x + y)^2 = (x^2 - 2xy + y^2)

First distribute the ^2 on the left side of the equation to each term inside the parenthesis:

x^2+ 2xy + y^2

Now pick one of the variables to solve for and isolate it:

(solving for x)

x^2 + 2xy + y^2 = x^2 - 2xy + y^2

x^2+ 2xy = x^2 - 2xy

2xy = -2xy

-x = x

x = 0

When you solve for y in the equation it will turn out to be 0 as well

7 0
3 years ago
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The perimeter of a rectangular park is 300 feet. The length of the park is 50 feet longer than the width.
bixtya [17]

Answer:

85 feet

Step-by-step explanation:

P=2L+2W where L is the length and W is the width. If the length is 50 feet longer than the width, we can write the expression L=50+W. Substituting into P=2L+2W we get P=2(50+W)+2W=100+2W+2W=100+4W. Since P=300, we can say 300=100+4W. Subtracting 100 from each side we get 200=4W. Dividing each side by 4 gives 50=W. Substituting this into L=50+W gives L=50+35=85. The length is 85 feet.

3 0
3 years ago
Solve this and get 20 points
VikaD [51]

take x =initial deposit amount. then make equation:

x+75.5+55.25-25.15-18.65 = 210.85

simplify:

x+86.95 = 210.85

x=210.85 - 86.95

x=123.90

so Initial deposit amount is $123.90

check:  210.85+18.65+25.15-55.25-75.5 = 123.9

123.9 = 123.9

4 0
3 years ago
How many kilometers are in 35 MI
Aleksandr-060686 [28]

Answer:

56.327km

Step-by-step explanation:

To find miles from kilometers times the number of kilometers(35) by 1.609 which approximately equals 56.327km.

8 0
3 years ago
Right answers plzzzz
Andrew [12]
D.  

a. 

b. 

hope that helped
5 0
3 years ago
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