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ExtremeBDS [4]
2 years ago
9

Okay here we go again number 8 does not have to be done ​

Mathematics
1 answer:
ollegr [7]2 years ago
7 0

8. (1/5)n - 8 <= 95

9. (b/45) + 7 > 5

10a. x < 2

10b. x > 2

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Any Netflix suggestions to watch?​
-Dominant- [34]

Answer:

stranger things

Step-by-step explanation:

6 0
2 years ago
For a given population of high school seniors, the Scholastic Aptitude Test (SAT) in mathematics has a mean score of 500 with a
tresset_1 [31]

Answer:

The probability that a randomly selected high school senior's score on mathematics part of SAT will be

(a) more than 675 is 0.0401

(b)between 450 and 675 is 0.6514

Step-by-step explanation:

Mean of Sat =\mu = 500

Standard deviation = \sigma = 100

We will use z score over here

 What is the probability that a randomly selected high school senior's score on mathe- matics part of SAT will be

(a) more than 675?

P(X>675)

Z=\frac{x-\mu}{\sigma}\\Z=\frac{675-500}{100}

Z=1.75

P(X>675)=1-P(X<675)=1-0.9599=0.0401

b)between 450 and 675?

P(450<X<675)

At x = 675

Z=\frac{x-\mu}{\sigma}\\Z=\frac{675-500}{100}

Z=1.75

At x = 450

Z=\frac{x-\mu}{\sigma}\\Z=\frac{450-500}{100}

Z=-0.5

P(450<X<675)=0.9599-0.3085=0.6514

Hence the probability that a randomly selected high school senior's score on mathematics part of SAT will be

(a) more than 675 is 0.0401

(b)between 450 and 675 is 0.6514

6 0
2 years ago
The graph represents the normal distribution of recorded weights, in pounds, of cats at a veterinary clinic.
marshall27 [118]

Please consider the graph.

We have been given that graph represents the normal distribution of recorded weights, in pounds, of cats at a veterinary clinic.  We are asked to choose the weights, which are within 2 standard deviations of the mean.

We can see from our graph that mean of the weights is 9.5 and standard deviation in 0.5.

The data point that would be below two standard deviation is: 9.5-2\times 0.5 that is 9.5-1=8.5.

The data point that would be above two standard deviation is: 9.5+2\times 0.5 that is 9.5+1=10.5.

Now we need to check the data points that lie within 8.5 and 10.5.

Upon looking at our given choices, we can see that 8.9, 9.5 and 10.4 pounds lie within 2 standard deviation of the mean.

Therefore, 8.9 lbs, 9.5 lbs and 10.4 lbs are correct choices.

8 0
3 years ago
Read 2 more answers
Can u pls help me with this question ​
Svet_ta [14]

Answer:

I think is 2/9 but I may be wrong

8 0
3 years ago
Treasury bills are paying a 4% rate of return. A risk-averse investor with a risk aversion of A = 1.85 should invest entirely in
kumpel [21]

Answer:

14.656%

Step-by-step explanation:

Data provided in the question:

Rate of return, r = 4% = 0.04

Risk aversion of A = 1.85

Standard deviation, σ = 24%

Now,

we have the relation

A = (E - r) ÷ σ²

E = expected return on portfolio

r = Risk free rate

on substituting the respective values, we get

1.85 = (E - 0.04) ÷ (0.24)²

or

0.0576 × 1.85 = (E - 0.04)

or

0.10656 + 0.04 = E

or

E = 0.14656 or

E = 0.14656 × 100% = 14.656%

8 0
2 years ago
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