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butalik [34]
4 years ago
13

Explain why there must be at least two lines on any given plane.

Mathematics
2 answers:
Over [174]4 years ago
8 0

There exists one plane through any three noncollinear points. Since the points cannot be on the same line, at least two lines would have to pass through any of the three points.

11Alexandr11 [23.1K]4 years ago
4 0
<span><u><em>The correct answer is: </em></u>
there must be at least two lines on any plane because a plane is defined by 3 non-collinear points.

<u><em>Explanation: </em></u>
Since a plane is defined by 3 non-collinear points, we could have: a line and a point not on that line; two intersecting lines; two parallel lines; or simply 3 non-collinear points.
For 3 non-collinear points: If none of the 3 points are collinear, then we could have 3 lines, 1 going through each point. These lines may or may not intersect. If two of the 3 points are collinear, then we have a line through those 2 points as well as a line through the 3rd point.. Again, these lines may intersect, or they may be parallel.</span>
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4 years ago
Another one of these, god help me
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Answer:

24x+48

Step-by-step explanation:

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3 years ago
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There is a stack of 8 cards each given a different number from 1 to 8. Suppose we select a card randomly from the stack, replace
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Answer:

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Ne4ueva [31]

The solution to the compound inequality given as 6b < 36 or 2b + 12 > 6 is b < 6 or b > -3

<h3>How to solve the compound inequality?</h3>

The compound inequality is given as:

6b < 36 or 2b + 12 > 6

Evaluate the like terms in the individual inequalities

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Divide the individual inequalities by the coefficients of b

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2 years ago
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