(1- cos2x) dx
= x - 1/2 sin2x + c
= x - 1/2 ( 2*sinx cosx) +c
= x - ((sinx) (cosx)) +c
Answer:
Step-by-step explanation:
Volume = 198 ft
length * width * height = 198
(x - 1) * (x + 4) * 3 = 198
(x - 1) * (x + 4) = 198/3
(x - 1) * (x + 4) = 66
x*x + x*4 -1*x - 1*4 = 66 {Use FOIL method to multiply}
x² + 4x - x - 4 = 66
x² + 3x - 4 =66
x² + 3x - 4 - 66 = 0
x² + 3x - 70 = 0
Now factorize.
x² + 10x - 7x - 7*10 = 0
x(x +10) - 7(x + 10 ) = 0
(x + 10)(x - 7) = 0
x - 7 = 0 {x + 10 is ignored because measurement cannot be in negative}
x = 7
length = x - 1 = 7 - 1 = 6ft
Width = x + 4 = 7 + 4 = 11 ft
A,F would never cross with B,E even if they where to go on forever
Hope this helps
The amount of space left with the snakd container inside the wastebasket=
=(volume of the wastebasket) - (volume of the sanak container)
Volume (cylinder)=area of the circle * height
1) We calculate the volume of a wastebasket:
area of the circle=πr²=π(5 in)²=25π in²
heigth=20 in.
Volume=25π in² * 20 in=500π in³.
2) we calculate the volume of the snack container:
area of the circle=πr²=π(4 in)²=16π in²
heigth=6 in.
Volume=16π in² * 6 in=96π in³
3) we calculate the amount of space left with the sanak container inside the wastebasket.
amount of space left=500π in³ - 96π in³=404π in³
404π in³=404 * 3.141592654...in³≈1269.2 in³
Answer: 404π in³ or ≈1269.2 in³
The answer is B. Once you combine the two amounts consumed (which you’d put them in like terms and reduce) you’d subtract the sum from 3
There for
1 1/4 = 1 2/8
1 2/8+7/8 = 1 9/8
1 9/8 = 2 1/8
2 1/8 is the sum of the amount consumed there for,
3- 2 1/8 = 7/8
If you solved with A you would essentially be adding a initial quart of 3 and 1 1 1/4 which assumes you added milk then drank 7/8 of a quart, C assumes you don’t consume any and you have 1 1/4 and 7/8 quarts of milk above the 3 quarts and D would leave you with 1.125 or 1 1/8 there for it is also incorrect.
