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Masteriza [31]
3 years ago
10

In pea plants, smooth pea shape is dominant to wrinkled pea shape. If a pea plant that is true-breeding for smooth pea shape is

crossed with a pea plant that is true-breeding for wrinkled pea shape, what will be true of the offspring?
Biology
1 answer:
Lostsunrise [7]3 years ago
7 0
They will all be smooth pea shape

The Genotype will be: Ss

Capital S being the dominant smooth pea shape and lowercase s being the recessive wrinkled shape
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In humans, black hair (B) is dominant over red hair (b) and having six fingers (F) is dominant over having five fingers (f). Sal
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Genotype  & Phenotype  

BbFf  - 4  

bbFf - 4

Bbff - 4

bbff- 4

Phenotype  

BbFf – Black Hair with six fingers

bbFf – red hair with six fingers

Bbff – Black hair with five fingers

Bbff – red hair with five fingers

Explanation:

Given

Black hair allele is represented by "B"

Red hair allele is represented by "b"

Trait of having six fingers is represented by "F"

Trait of having five fingers is represented by "f"

Also , B is dominant over b and F is dominant over f

Genotype of sally having black hair and five fingers when her father has red hair is  Bbff

Genotype fo Bill having red hair and six fingers  when his mother had five fingers is bbFf

Bbff * bbFf

Bf         bf         Bf         bf

bF BbFf bbFf BbFf bbFf

bf Bbff         bbff         Bbff         bbff

bF BbFf bbFf BbFf bbFf

bf Bbff         bbff         Bbff         bbff

Genotype  & Phenotype  

BbFf  - 4  

bbFf - 4

Bbff - 4

bbff- 4

Phenotype  

BbFf – Black Hair with six fingers

bbFf – red hair with six fingers

Bbff – Black hair with five fingers

Bbff – red hair with five fingers

5 0
3 years ago
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