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Gnesinka [82]
3 years ago
7

I don’t know this and need help with the answer

Mathematics
1 answer:
ki77a [65]3 years ago
4 0
9+10=21 that is the answer
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Which of the following values are zeros for the function below g(x)=(x2+4x-12)(x-3)
Brilliant_brown [7]

Answer:

<h2>-6, 2 and 3</h2>

Step-by-step explanation:

g(x)=(x^2+4x-12)(x-3)=(x^2+6x-2x-12)(x-3)\\\\=[x(x+6)-2(x+6)](x-3)=(x+6)(x-2)(x-3)\\\\\text{The zeros for}\ g(x)=0:\\\\(x+6)(x-2)(x-3)=0\iff x+6=0\ \vee\ x-2=0\ \vee\ x-3=0\\\\x=-6\ \vee\ x=2\ \vee\ x=3

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3 years ago
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This question simply asks for 
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The answer is 1.001 pounds.
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