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Gnesinka [82]
3 years ago
7

I don’t know this and need help with the answer

Mathematics
1 answer:
ki77a [65]3 years ago
4 0
9+10=21 that is the answer
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An Archer shoots an arrow horizontally at 250 feet per second. The bullseye on the target and the arrow are initially at the sam
Genrish500 [490]

Answer:

<h2>1.84feet</h2>

Step-by-step explanation:

Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;

Range R = U\sqrt{\frac{H}{g} }

U is the velocity of the arrow

H is the maximum height reached = distance below the bullseye reached by the arrow.

R is the horizontal distance covered i.e the distance of the target from the archer.

g is the acceleration due to gravity.

Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?

On substitution,

60 = 250\sqrt{\frac{H}{32}} \\\frac{60}{250} = \sqrt{\frac{H}{32}}\\\frac{6}{25} = \sqrt{\frac{H}{32}

Squaring both sides we have;

(\frac{6}{25} )^{2} = (\sqrt{\frac{H}{32} } )^{2} \\\frac{36}{625} =  \frac{H}{32} \\625H = 36*32\\H = \frac{36*32}{625} \\H = 1.84feet

The arrow will hit the target 1.84feet below the bullseye.

5 0
3 years ago
Which rational graph has a minimum near x=-2 and a horizontal asymptote at y=1?
Arada [10]

Answer:

Graph A.

Step-by-step explanation:

The graph has a local minimum around x=-2 since it slightly curves downwards around this region. Moreover, the graph of the rational function has a horizontal asymptote at y=1 since the graph approaches this horizontal line but never touches nor crosses it

7 0
3 years ago
HELP!!! NEED HELP!!!!
blsea [12.9K]

Answer:

C

Step-by-step explanation:

6 0
3 years ago
Solve for Inequality
uysha [10]

Answer:

x > -1

Step-by-step explanation:

Divide the whole inequality by 9.

(\frac{x}{3}+1)>\frac{6}{9}

Subtract 1.

\frac{x}{3} > \frac{2}{3} - 1

\frac{x}{3} > -\frac{1}{3}

Multiply by 3.

x > -1

6 0
3 years ago
Find
Westkost [7]

Answer:

dy/dx = -b/a cot α

Step-by-step explanation:

x² / a² + y² / b² = 1

Take derivative with respect to x.

2x / a² + 2y / b² dy/dx = 0

2y / b² dy/dx = -2x / a²

dy/dx = -b²x / (a²y)

Substitute:

dy/dx = -b²a cos α / (a²b sin α)

dy/dx = -b cos α / (a sin α)

dy/dx = -b/a cot α

8 0
3 years ago
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