You can use a frequency table for steak tasting, where each numbers represents the steak that was the chosen as the best.
<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:
..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
Part A = She incorrectly add 1 (4/4) with 3/4, so instead of getting 7/4 she got 8/4.
Part B=She needs 28/4 (7) cups for 4 batches because 4/1x7/4=28/4.
Answer:
-4
Step-by-step explanation:
The function is linear; therefore, the slope of the line joining any two points is the same.
We take any two points from the table and compute the slope or rise/ run between them— let is take points (-4, -2) and (-2, -10).
The slope 
of the line joining the points is
The slope of the function is -4.
V = L * W * H
V = (1/2)(1/4)(2/3)
V = (1 * 1 * 2) / (2 * 4 * 3)
V = 2/24 reduces to 1/12 m <===
