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3 years ago

5

Write a piecewise function for the graph

1 answer:

netineya [11]3 years ago

5 0

Answer:

You can used it to help me out with a good time with this and

Step-by-step explanation:

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If j= 14, find the value of 1/2j.

Yakvenalex [24]

Answer:7

Step-by-step explanation:

1/2 of j is the same as j ÷ 2

14 ÷ 2 = 7

8 0

3 years ago

Please someone help me on how to do grids?

mafiozo [28]

Answer:

25

Step-by-step explanation:

Question: The distance between P and T on the coordinate grid is __ units. (Input whole numbers only.)

Answer + Step-by-step explanation:

Step 1. Find where point P is located at

Answer: (-10, 15)

Step 2. Find where point T is located at

Answer: (15, 15)

Step 3. Find the distance between point P and T.

Answer: (25) Steps in image

4 0

3 years ago

Read 2 more answers

If T is the midpoint of segment RS then, Segment RT is congruent to segment TS..<br> Help please!!!!

omeli [17]

Answer:

Definition of Midpoint

Step-by-step explanation:

Since T is the midpoint then it is equadistant from R to T and T to S

3 0

3 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

£1800 is invested at4% compound interest per year.

deff fn [24]

2000=1800(1.04)^t,,log(1.11)/log(1.04)=t use the calculator,,,hope it helps :-)

3 0

3 years ago