Given:
Quadrilateral ABCD has vertices A(–1, –2), B(–1, 3), C(4, 3) and D(4, –2).
It's dilated by a factor of 2 with the center of dilation at the origin.
To find:
The coordinates of the resulting quadrilateral A'B'C'D'.
Solution:
The figure dilated by a factor of 2 with the center of dilation at the origin. So, the rule of dilation is
Using the above rule, we get
Therefore, the coordinates of the resulting quadrilateral A'B'C'D' are A'(-2,-4), B'(-2,6), C'(8,6) and D'(8,-4).