The steps to determine whether the pillars have the same volume are;
First, we must know that the volume of an object of uniform surface area is the product of its Area and height.
The uniform area of each pillar is then evaluated and if equal;
Both pillars can be concluded to have the same volume.
We must first recall that for various shapes, the volume of the shape is a function of its height.
For example: a A cylinderical pillar and a rectangular prism pillar;
Volume of a cylinder = πr²h
Volume of a Cuboid = l × w × h
Since h = h.
Therefore, for both pillars to have the same volume; their Areas must be equal.
πr² = l × w
Learn more about Area and volume here
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Answer:
A book about a mass of 1 kilogram, but that isn't the only answer.
Explanation:
There's many objects with a mass of one kilogram like one liter of water, a pineapple, bag of sugar etc.
Answer:
1.66
Step-by-step explanation:
Calculation to find the standard deviation for the random variable X of the number of students who work full time in samples of size
Using this formula
Standard deviation(X)=√np(1−p)
Where,
n represent the number of students=16
p represent the percentage of all students who work full time=22
Let plug in the formula
Standard deviation(X)=√16(0.22)(1−0.22)
Standard deviation(X)=√(3.52)(0.78)
Standard deviation(X)=√2.7456
Standard deviation(X)=1.656
Standard deviation(X)=1.66 (Approximately)
Therefore the standard deviation for the number of students who work full time in samples of size 16 will be 1.66
Take a look at the attachment below. It fills in for the attachment that wasn't provided in the question -
An oblique pyramid is one that has a top not aligned with the base. Due to this, the height of the pyramid connects with two vertices at its ends to form a right angle present outside the pyramid, knowing that it is always perpendicular to the base. There is no difference between the calculations of the volume of an oblique pyramid and a pyramid however -
<u><em>And thus, you're solution is 5 cm^3, or in other words option b!</em></u>
