Answer:
1. (x+8)(x-4)
2. 3x-20
Step-by-step explanation:
1. x² + 4x – 32
x² + 8x - 4x - 32
x (x+8) - 4 (x+8)
one of the x+8's is cancelled out then you have (x+8)(x-4)
2. x2 + x - 20
2x+x-20
3x-20
Answer:
89
Step-by-step explanation:
3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions