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Setler79 [48]
3 years ago
8

Using the graph of f(x) = log2x below, approximate the value of y in the equation 22y = 5.

Mathematics
2 answers:
Naddika [18.5K]3 years ago
4 0
The correct question is
Using the graph of f(x) = log2x below, approximate the value of y in the equation 2^(2y) = 5

we have 
2^(2y) = 5--------------> applying base 2 logarithm both members
2y*log2(2)=log2(5)
log2(2)=1
then
2y=log2(5)
y=[log2(5)]/2

using the graph
for  x=5  the approximate  value of log2(5) is 2.3
see the attached figure
so
y=[log2(5)]/2--------> y=[2.3]/2----------> y=1.15

the answer is
the approximate value of y is 1.15

Harrizon [31]3 years ago
3 0

Answer:

<h2><u>y = 1.16</u></h2>

Step-by-step explanation:

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

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Read 2 more answers
Use quadratic formula to solve 1-6x^2-x​
eduard

Answer:

(3x-1)(2x+1)

Step-by-step explanation:

1-6x^2-x=0

-6x^2-x+1=0

6x^2+x-1=0

6x^2+(3-2)x-1=0

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6 0
3 years ago
What is the value of (16^3/2)^1/2
Alika [10]

<u><em>Answer: =1024. *The answer must be have positive sign.*</em></u>

Step-by-step explanation:

This question's it's about the order of operations. p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left to right.

do exponents first.

16³/2=4098=2048¹/2

2048¹=2048

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divide left to right.

2048/2=1024

Hope this helps!

Thanks!

Have a great day!

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3 years ago
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Answer:

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