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3 years ago

Using the graph of f(x) = log2x below, approximate the value of y in the equation 22y = 5.

Mathematics

2 answers:

Naddika [18.5K]3 years ago

4 0

The correct question is
Using the graph of f(x) = log2x below, approximate the value of y in the equation 2^(2y) = 5

we have
2^(2y) = 5--------------> applying base 2 logarithm both members
2y*log2(2)=log2(5)
log2(2)=1
then
2y=log2(5)
y=[log2(5)]/2

using the graph
for x=5 the approximate value of log2(5) is 2.3
see the attached figure
so
y=[log2(5)]/2--------> y=[2.3]/2----------> y=1.15

the answer is
the approximate value of y is 1.15

Harrizon [31]3 years ago

3 0

Answer:

Step-by-step explanation:

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

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