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pickupchik [31]

4 years ago

6

Choose the steps below in the appropriate order to explain why the sky is blue. a.White light interacts with molecules in the at

mosphere. b.White light with all colors is emitted by the sun. c.Light that is primarily blue comes from all directions in the sky. d.When interacting with molecules, blue light with shorter wavelength scatters more in al

1 answer:

Ira Lisetskai [31]4 years ago

6 0

Answer:

The correct order is (b), (a), (d), (c).

Explanation:

Given:

Correct order is as follows,

(b) White light with all colors is emitted by the sun.

(a) White light interacts with molecules in the atmosphere.

(d) When interacting with molecules, blue light with shorter wavelength scatters more in all direction.

(c) Light that is primarily blue comes from all directions in the sky.

Therefore, the correct order is (b), (a), (d), (c).

You might be interested in

1. Two astronauts are 2.00 m apart in their spaceship. One speaks to the other. The conversation is transmitted to earth via ele

Veronika [31]

Answer:

$1.6949*10^6 m$

Explanation:

Our values are

$d=2m$

$v=354m/s$

We can find the time through

$t=\frac{d}{v}$

$t=\frac{2}{354}$

$t=5.64*10^{-3}s$

The expression for the distance between the Earth and the spaceship is as follow:

$d=ct$

Where c is Light speed, and t our previous time.

$d= (3*10^8)(5.64*10^{-3})$

$d= 1.6949*10^6m$

Therefore the distance between the Eath and the Spaceship is $1.6949*10^6$ m

4 0

4 years ago

What are the advantages of using a telescope compared to making observations with the naked eye?

lara31 [8.8K]

The naked eye is very limited. Unlike the telescope which can see far away.

4 0

4 years ago

A 3.9 kg block is pushed along a horizontal floor by a force of magnitude 30 N at a downward angle θ = 40°. The coefficient of k

Luba_88 [7]

Answer:

The frictional force $F_{fri} =$ 6.446 N

The acceleration of the block a = 6.04 $\frac{m}{s^{2} }$

Explanation:

Mass of the block = 3.9 kg

$\theta = 40$ °

$\mu$ = 0.22

(a). The frictional force is given by

$F_{fri} = \mu R_{N}$

$R_{N} = mg \cos \theta$

$R_{N} =$ 3.9 × 9.81 × $\cos 40$

$R_{N} =$ 29.3 N

Therefore the frictional force

$F_{fri} =$ 0.22 × 29.3

$F_{fri} =$ 6.446 N

(b). Block acceleration is given by

$F_{net} = F - F_{fri}$

F = 30 N

$F_{fri}$ = 6.446 N

$F_{net}$ = 30 - 6.446

$F_{net}$ = 23.554 N

The net force acting on the block is given by

$F_{net} = ma$

23.554 = 3.9 × a

a = 6.04 $\frac{m}{s^{2} }$

This is the acceleration of the block.

8 0

3 years ago

A football quarterback runs 15.0 m straight down the playing field in 3.00 s. He is then hit and pushed 3.00 m straight backward

algol [13]

Answer:

a) $v_{1}=14.29m/s\\v_{2}=9.25m/s\\v_{3}=6.36m/s$

b) $v=+9.97m/s$

Explanation:

From the exercise we know that

$x_{1} =15m, t_{1}=3s$

$x_{2} =-3m, t_{1}=1.74s$

$x_{3} =29m, t_{3}=5.20s$

From dynamics we know that the formula for average velocity is:

$v=\frac{x_{2}-x_{1} }{t_{2}-x_{1} }$

a) For the three intervals:

$v_{1}=\frac{x_{2}-x_{1} }{t_{2}-t_{1} }=\frac{(-3-15)m}{(1.74-3)s}=14.29m/s$

$v_{2}=\frac{x_{3}-x_{2} }{t_{3}-t_{2} }=\frac{(29-(-3))m}{(5.20-1.74)s}=9.25m/s$

$v_{3}=\frac{x_{3}-x_{1} }{t_{3}-t_{1} }=\frac{(29-15)m}{(5.20-3)s}=6.36m/s$

b) The average velocity for the entire motion can be calculate by the following formula:

$v=\frac{v_{1}+v_{2}+v_{3} }{n} =\frac{(14.29+9.25+6.36)m/s}{3}=+9.97m/s$

8 0

3 years ago

una bala de 20 g choca con un fango como se muestra en la figura y penetra una distancia de 6 cm antes de detenerse. calcule la

aleksklad [387]

Answer:

A 20g bullet collides with a mud as shown in the figure and penetrates a distance of 6cm before stopping. calculate the braking force f if the input speed was 80m/s

Explanation:

Given that,

A bullet of mass

M = 20g = 0.02kg

The bullet is fired into a mud initially at rest

The bullet penetrate a distance of 6cm in the mud

S = 6cm = 0.06m

The input velocity into the mud is 80m/s, this implies that, the initial velocity is 80m/s

U = 80m/s

So, the bullet stop after a distance of 6cm, so the final velocity is 0m/s

V = 0m/s

So, we need to find the braking force

Breaking force (F) is given as

F = ma

Where m is mass and 'a' is deceleration

So, we need to find the deceleration, using equation of motion

V² = U² + 2as

0² = 80² + 2 × a × 0.06

0 = 6400 + 0.12a

0.12a = -6400

a = -6400 / 0.12

a = - 53,333.33 m/s²

So, the negative sign shows that the bullet is decelerating

So, a = 53,333.33 m/s²

So, breaking force

F = ma

F = 0.02 × 53,333.33

F = 1066.67 N

The breaking force is 1066.67 N

In spanish

Dado que,

Una bala de masa

M = 20 g = 0.02 kg

La bala se dispara en un lodo inicialmente en reposo

La bala penetra una distancia de 6 cm en el barro.

S = 6 cm = 0.06 m

La velocidad de entrada al lodo es de 80 m / s, esto implica que la velocidad inicial es de 80 m / s

U = 80 m / s

Entonces, la bala se detiene después de una distancia de 6 cm, por lo que la velocidad final es de 0 m / s

V = 0 m / s

Entonces, necesitamos encontrar la fuerza de frenado

La fuerza de ruptura (F) se da como

F = ma

Donde m es masa y 'a' es desaceleración

Entonces, necesitamos encontrar la desaceleración, usando la ecuación de movimiento

V² = U² + 2as

0² = 80² + 2 × a × 0.06

0 = 6400 + 0.12a

0.12a = -6400

a = -6400 / 0.12

a = - 53,333.33 m / s²

Entonces, el signo negativo muestra que la bala se está desacelerando

Entonces, a = 53,333.33 m / s²

Entonces, fuerza de ruptura

F = ma

F = 0.02 × 53,333.33

F = 1066.67 N

La fuerza de ruptura es 1066.67 N

7 0

4 years ago