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3 years ago

How do I answer this wuestion? -9/12-(-7/4)=

Mathematics

2 answers:

Nady [450]3 years ago

7 0

=9:12 + 7:4 | T
= -0,75 + 1,75 | -0,75
= 1

Tema [17]3 years ago

4 0

The answer is 1. just subtract the fractions and boom. answer.

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What two numbers are located 5/8 of a unit from 1/6 on a number line?

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First find the common denominator. It would be 24. For 8 to get to 24 you have to multiply it by 3. So 8*3=24 and 5*3=15. For 6 to get to 24 you have to multiply it by 4. So 6*4=24 and 1*4=4. Our fractions are now at 15/24 and 4/24. 15+4 is 19 and 15-4 is 11. Your answers are 19/24 and 11/24.

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3 years ago

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Step-by-step explanation:

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3 years ago

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Fill in the question mark ?5

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I don't really understand your question , can you rephrase it ?

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3 years ago

The Pythagorean Theorem ONLY works on which triangle?

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Step-by-step explanation:

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3 years ago

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Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot

Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

$\frac{dm}{dt} = -\frac{t}{\tau}$

Where:

$m$ - Current mass of the isotope, measured in kilograms.

$t$ - Time, measured in days.

$\tau$ - Time constant, measured in days.

The solution of the differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

$\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}$

$\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }$

The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

$t_{1/2} = \tau \cdot \ln2$

$t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2$

The half-life difference between isotope B and isotope A is:

$\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|$

If $\frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9$ , $t_{A} = 33\,days$ and $t_{B} = 43\,days$ , the difference in the half-lives of the isotopes is:

$\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|$

$\Delta t_{1/2} \approx 65.788\,days$

The approximate difference in the half-lives of the isotopes is 66 days.

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3 years ago

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