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Ivenika [448]
3 years ago
11

Write a decimal equation that has a product of 3.15

Mathematics
1 answer:
Vaselesa [24]3 years ago
4 0
<span>you could have 3.15=100 times 0.0315, 10 times 0.315.</span>
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I don't understand what I have to do. HELP
Volgvan
Basically what you are doing is trying to find the square root of 8. What you need to do is find what would go into the number 8 equally so, you are basically finding the multiples
8 0
2 years ago
A circle with the equation (x + 6)2 + (y + 3)2 = 16 is reflected over the line x = 2.
fomenos

Answer: (x-10)^{2}+(y+3)^{2}=16

Step-by-step explanation:

We know the center of the original circle is (-6, -3). After reflecting this over the line x=2, the new center is now (10, -3).

Thus, the equation of the circle is (x-10)^{2}+(y+3)^{2}=16.

6 0
1 year ago
A rectangular plot of land is to be enclosed by a fence. One side is along a river, and does not need to be enclosed. If the tot
Bad White [126]

Answer:

Width 150 meters.

Length = 350 meters.

Step-by-step explanation:

Let us assume the  width of  the fence = k meters

So, both sides = k + k = 2k meters

Also, the TOTAL fencing length = 600 m

So, the one side length of the fence = (600 - 2 k) meters

AREA = LENGTH x WIDTH

⇒ A(k)  = (600 - 2k) (k)

or, A =  -2k² + 600 k

The above equation is of the form: ax² +bx +  C

Here: a  = - 2 , b = 600 and C = 0

As a< 0, the parabola opens DOWNWARDS.

Here, x value is given as:  x = \frac{-b}{2a}

Solving for the value of k similarly, we get:

k = \frac{-b}{2a}  = \frac{600}{2(-2)}  = 150

Thus the desired width = k = 150 meters

So, the desired dimensions of the plot  is width 150 meters.

And length = 650 - 2k = 650 - 300 = 350 meters.

5 0
2 years ago
Is 24.48 a interger​
Sergio039 [100]

This is not an integer; an integer is a whole number that can be positive, negative, or zero such as -1, 0, and 1.

7 0
2 years ago
Read 2 more answers
Tina is saving to buy a notebook computer. She has two options. The first option is to put $500 away initially and save $10 ever
Alexxandr [17]

Answer:

Tina would save the same amount using either option after 20 months.

With either option, Tina would save $700.

Step-by-step explanation:

This problem can be modeled by a first order equation:

Where Tina's saved money after n months is:

S(n) = S(0) + rn, where S(0) is the money put away initially and r is how much she saves every month.

The first option is to put $500 away initially and save $10 every month, so:

S_{1}(n) = 500 + 10n

The second option is to put $100 away initially and save $30 every month, so:

S_{2}(n) = 100 + 30n

After how many months would Tina save the same amount using either option?

It will happen at the month n in which S_{1}(n) = S_{2}(n), so:

S_{1}(n) = S_{2}(n)

500 + 10n = 100 + 30n

500 - 100 = 30 - 10n

400 = 20n

20n = 400

n = \frac{400}{20}

n = 20.

Tina would save the same amount using either option after 20 months.

How much would she save with either option?

We can choose S_{1}(20) or S_{2}(20), since they are equal

S_{1}(20) = 500 + 10(20) = 500 + 200 = 700

With either option, Tina would save $700.

3 0
3 years ago
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