Help???? ill take help from anyone

Point p is the midpoint of DE. DP =3x + 2 and DE = 10x - 12. What is the length of DP

shepuryov [24]

If P is the midpoint of DE then
DE = 2(DP)
10x - 12 = 2(3x + 2)
10x - 12 = 6x + 4
10x - 6x = 4 + 12
4x = 16
x = 16/4
x = 4

DP = 3x + 2 = 3 * 4 + 2 = 12 + 2 = 14 units

6 0

3 years ago

Read 2 more answers

Question:

AleksandrR [38]

Answer:

x=8 and y=3 (So, yes!)

Step-by-step explanation:

I will solve your system by substitution.

(You can also solve this system by elimination.)

−x+4y=4;−x+3y=1

Step: Solve −x+4y=4 for x:

−x+4y+−4y=4+−4y(Add -4y to both sides)

−x=−4y+4

-x/-1 = -4y+4/-1 (Divide both sides by -1)

x=4y−4

Step: Substitute 4y−4 for x in −x+3y=1:

−x+3y=1

−(4y−4)+3y=1

−y+4=1(Simplify both sides of the equation)

−y+4+−4=1+−4(Add -4 to both sides)

−y=−3

-y/-1 = -3/-1 (Divide both sides by -1)

y=3

Step: Substitute 3 for y in x=4y−4:

=4y−4

x=(4)(3)−4

x=8(Simplify both sides of the equation)

Answer:

x=8 and y=3

4 0

1 year ago

What is 2(5)+3(4)+5^2? (The ^ means the exponent)

castortr0y [4]

I believe the answer is 47.

6 0

3 years ago

Both the La Plata river dolphin (Pontoporia blainvillei) and

Citrus2011 [14]

Answer:

1. A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin; 2. The radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball; 3. The volume of the larger ball is 3 orders of magnitude bigger than the volume of the smaller ball.

Step-by-step explanation:

If we expressed a number as:

$\\ N = a * 10^{b}$ (1)

Where

$\\ \frac{1}{\sqrt{10}} \leq a < \sqrt{10}$ (2)

or

$\\ 1 \leq a < 10$ (3)

Then, b represents the order of magnitude of such a number (Order of magnitude (2020), in Wikipedia).

The order of magnitude can be defined as "...the smallest power of ten needed to represent a quantity" (Weisstein, Eric W. "Order of Magnitude". From MathWorld--A Wolfram Web Resource).

Having gathered all this information, we can proceed as follows:

<h3>First case</h3>

The La Plata river dolphin weighs between 30 and 50kg and the sperm whale weighs between 35,000 and 40,000kg.

Then, considering (1) and (3) to express the dolphin and whale's weight (since in this way the order of magnitude is the same as the exponent part in the scientific notation):

$\\ 30kg \leq Dolphin_{weight} \leq 50kg$

$\\ 3*10^{1}kg \leq Dolphin_{weight} \leq 5*10^{1}kg$

$\\ 35000kg \leq Whale_{weight} \leq 40000kg$

$\\ 3.5*10^{4}kg \leq Whale_{weight} \leq 4.0*10^{4}kg$

Since the range for the weights are in the same order of magnitude for both dolphin and whale (considering the definition above):

$\\ Dolphin_{weight} = 10^{1}\;(order\;of\;magnitude=1)$

$\\ Whale_{weight} = 10^{4}\;(order\;of\;magnitude=4)$

Then

$\\ \frac{Whale_{weight} = 10^{4}}{Dolphin_{weight} = 10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = \frac{10^{4}}{10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{4-1}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{3}$

Thus

A sperm whale is 3 orders of magnitude heavier than a La Plata river dolphin.

<h3>Second case</h3>

Following the same reasoning, we can conclude that the radius of the larger ball is one (1) order of magnitude bigger than the radius of the smaller ball:

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = \frac{10^{1}}{10^{0}}$