All categories

2 years ago

What's the system of linear equations by the solution graphed below

Mathematics

2 answers:

AfilCa [17]2 years ago

8 0

D should be the correct answer. <span>Hope this helps! Brainliest would be appreciated!</span>

bija089 [108]2 years ago

7 0

<h2>Answer:</h2>

The system of linear equation that is graphed is:

Option: A

A. y > -1 and y ≤ -x

<h2>Step-by-step explanation:</h2>

By looking at the graph we observe that the first inequality:

Is a strict inequality (since the graph is a dotted line which passes through (0,-1) and is a horizontal line parallel to the x-axis )

Also, the shaded region is above the line i.e. towards the origin.

This means that the line passes the zero point test.

Hence, the inequality which satisfies this condition is:

y > -1

Also, the graph of the second inequality:

Is a solid line (i.e. the inequality is not strict) and the line satisfies the relation y= -x and the shaded region lie below the line i.e. the inequality is given by:

y ≤ -x

You might be interested in

- 1/5 - (-5/11) <br> p.s this for my online learning assignment , help me pls :)

Murrr4er [49]

Here is a picture of the answer:

6 0

2 years ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

<u>Answer:</u>

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

<u>Solution: </u>

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

6 0

3 years ago

Find the sum of the following infinite geometric series, if it exists. 4+3.2+2.56+2.048+...

mel-nik [20]

14.848 might be not sure

3 0

2 years ago

Read 2 more answers

Paula a college student earned $3,600 one summer during the following semester she spent $2500 for tuition $650 for rent and $43

Fed [463]

The fraction you are looking for is expenses/earnings

So (2500+650+434)/3600
=224/225

If you want to turn this into a percentage just multiply by 100, to give you 99.56%.

3 0

2 years ago

What is the volume of the prism below?

Triss [41]

Step-by-step explanation:

please subscribe my mom's channel those who subscribed my mom's channel

8 0

2 years ago