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inna [77]
3 years ago
7

What is the range of the function f(x) = 4 − 2(x + 3)^2?

Mathematics
1 answer:
mash [69]3 years ago
4 0

Answer:

(-infinity, 4]

Step-by-step explanation:

The range is the possible y values

The smallest that (x+3)^2 can be is zero

f(x) = 4 − 2(x + 3)^2

f(x) = 4 -2(0) = 4

This is the maximum value

As the square term gets bigger we are subtracting a larger amount and it will get more negative

Let x = infinity, x+3 = infinity and infinity ^2 = infinity  and 2* infinity = infinity

f(x) = 4 - infinity

     = -infinity

The range is -infinity to 4

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What is the value of 5-8×(7-15+8)
salantis [7]

Answer:

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Step-by-step explanation:


6 0
3 years ago
Pls help tap picture to see the three problems
valentinak56 [21]
1. Slope intercept form. First find two points to get slope: (0,-3) and (-3,-4). Slope is
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Y=1/3x + b
-3 = 1/3(0) + b
-3 = b so your slope intercept equation is
Y = 1/3x - 3

2. Rate of Change is slope. Your points are (0,10) and (24,6) so slope is (6-10)/(24-0)
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3. Standard form is ax + by =c
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3 years ago
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