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Phantasy [73]
4 years ago
14

the perimeter of parallelogram ABCD is 78 cm. AD is more than twice AB. find the lengths of all four sides of ABCD.

Mathematics
1 answer:
diamong [38]4 years ago
6 0
AD is the width side of the perimeter is 78
So they said AD is more than twice AB
78 multiply 2= 156
You have 2 width 78+78
You have 2 length 156+156
Add four sides together
Hope this help you!
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The length of a rectangle is 7 ft longer than twice the width. If the perimeter is 92 ft find the length and width of the rectan
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Width of the rectangle is 13 ft and length of the rectangle is 33 ft

<u>Step-by-step explanation:</u>

Step 1:

Given perimeter of the rectangle = 92 ft. Let the width be x, then the length of the rectangle = 2x + 7. Use the formula for perimeter of a rectangle = 2(length + width) to find the dimensions.

92 = 2(2x + 7 + x) = 2(3x + 7) = 6x + 14

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⇒ x = 78/6

∴ x = 13 ft

⇒ Width of the rectangle = 13 ft

∴ Length of the rectangle = 2x + 7 = 26 + 7 = 33 ft

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