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nikitadnepr [17]
3 years ago
10

given the midpoint of segment KL is M (1, -1) and L (8 ,-7) what are the coordinates of the other endpoint K

Mathematics
2 answers:
andrey2020 [161]3 years ago
7 0

The answer is (-6, 5) for K.

In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Kx + Lx)/2 = Mx

(Kx + 8)/2 = 1

Kx + 8 = 2

Kx = -6

And now we do the same thing for y values

(Ky + Ly)/2 = My

(Ky + -7)/2 = -1

Ky + -7 = -2

Ky = 5

This gives us the final point of (-6, 5)

Elodia [21]3 years ago
4 0

Answer:

(-6,5).

Step-by-step explanation:

We are given that M is a midpoint of KL

The point L is at (8,7).

The midpoint M is at (1,-1).

We have to find the value of other point K

Let point of K is at (x,y)

We know that midpoint formula

x=\frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}

x_1=x,x_2=8,y_1=y,y_2=-7,x=1,y=-1

Using the formula and substitute the values in the given formula

1=\frac{x+8}{2}

x+8=2

x=2-8=-6

-1=\frac{y-7}{2}

y-7=-2

y=-2+7

y=5

Hence, the coordinate of other point K is at(-6,5).

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Line segment ON is perpendicular to line segment ML.
garik1379 [7]

Answer:

24 units

Step-by-step explanation:

OM = ON, so

OP= 13-8

That means OP is 5.

Using the Pythagorean Theorom to find MP:

5^2+b^2=13^2

25+b^2=169

b^2=169-25

b^2=144

B=12

This means MP =12.  ML is twice as long as MP. 12x2=24

3 0
3 years ago
HI I NEVER KNEW HOW TO DO THIS BUT I DO SO CAN YALL REALLY HELP ME PLEASE
Aliun [14]

Answer:

A. 4/15 and 0.26 repeating

Step-by-step explanation:

As we see in the long division, 4/15 is equal to 0.26666666666666666666666 (or. 0.26 repeating).

4/15

4 doesn't go into 15, so add a zero.

4.0/15

40 goes into 15 twice

40 - 30 is 10. 10 is less than 15 so add a 0.

4.00

100 goes into 15 6 times.

100 - 90 is 10. 10 is less than 15, so add a 0.

The 100 into 15 process repeats, so there's your answer.

8 0
3 years ago
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During a manufacturing process, a metal part in a machine is exposed to varying temperature conditions. The manufacturer of the
mars1129 [50]

Answer:

Yes, it will reach or exceed 141 degree F

Step-by-step explanation:

Given equation that shows the temperature T in degrees Fahrenheit x minutes after the machine is put into operation is,

T = 0.005x^2 + 0.45x + 125

Suppose T = 141°F,

\implies 141 = 0.005x^2 + 0.45x + 125

\implies 0.005x^2 + 0.45x + 125 - 141 =0

\implies 0.005x^2 + 0.45x - 16=0

Since, a quadratic equation ax^2 + bx + c =0 has,

Real roots,

If Discriminant, D = b^2 - 4ac \geq 0

Imaginary roots,

If D < 0,

Since, 0.45^2 - 4\times 0.005\times -16 = 0.2025 + 32 > 0

Thus, roots of -0.005x² + 0.45x + 125 are real.

Hence, the temperature can reach or exceed 141 degree F.

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3 years ago
RSTU is a rectangle. If UT = x + 10 and RS=20,<br> find x.<br> a. 30<br> b. 10<br> c. 20<br> d. 150
Vinvika [58]
B issssssss the answerrrrrrrrrr
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Rama09 [41]

6 (x+5)

I hope this helps :))

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