3 years ago

What is the Interquartile Range (IQR) of the pumpkin weights? a) 10 b) 4 c) 15 d) 8

Mathematics

2 answers:

oksano4ka [1.4K]3 years ago

4 0

Answer:

4 which is b

Step-by-step explanation:

Alborosie3 years ago

3 0

I think the answer will be c

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Consider the function f(x) = x^3 - 7x^2 - 2x + 14

mars1129 [50]

Answer:

There are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:x^3\:-\:7x^2\:-\:2x\:+\:14$

To get the zeros of $f(x)$ , set $y$ or $f(x) =0$

$0=x^3-7x^2-2x+14$

$x^3\:-\:7x^2\:-\:2x\:+\:14=\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)$

$\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)=0$

Using the zero factor principle:

$\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-7=0\quad \mathrm{or}\quad \:x+\sqrt{2}=0\quad \mathrm{or}\quad \:x-\sqrt{2}=0$

solving

$x-7=0$

$x=7$

$x+\sqrt{2}=0$

$x=-\sqrt{2}$

$x-\sqrt{2}=0$

$x=\sqrt{2}$

Therefore, there are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

8 0

3 years ago

Ima need sum more help

laiz [17]

Answer:

Step-by-step explanation:

Because yes

4 0

3 years ago

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Allison has five times as many baseball cards and football cards in all she has 120 baseball and football cards how many basebal

ValentinkaMS [17]

I think you do 120 divided by 5, but I could be wrong.

6 0

3 years ago

\dfrac {15}k

Monica [59]

Answer:

Step-by-step explanation:

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Also can anyone help with these problems too?

d1i1m1o1n [39]

Answer:

6. a

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7. b

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8. d

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9. d

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3 years ago