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postnew [5]
3 years ago
7

Which of the following inequalities does NOT contain the solution b = 4? A. 2 + b is greater than or equal to 2 B. 3b is less th

an or equal to 14 C. 8 - b is less than or equal to 15 D. b - 3 is greater than or equal to 5
Mathematics
2 answers:
svetoff [14.1K]3 years ago
8 0
D.  b-3 would be 1, which is not greater than or equal to 5
Lesechka [4]3 years ago
7 0
A) 2+b ≥ 2 ----> b ≥ 0

"b" may equal to 4.

B) 3b ≤ 14
for b=4 ; 12 ≤ 14 ---> It is true.
So "b" may equal to 4.

C) 8-b ≤ 15
8-15 ≤ b
-7 ≤ b
"b" may equal to 4.

D) b-3 ≥ 5
b ≥ 3+5
b ≥ 8
b cant equal to 4.
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Can you answer this math homework? Please!
inessss [21]

Answer:

m = -3 and b = -3

Step-by-step explanation:

No solution at all when you graph the two equations

8 0
3 years ago
Find the sum of this infinite geometric series where a1=0.3 and r=0.1
ratelena [41]

Answer:

1/3

Step-by-step explanation:

The formula for computing the sum of an infinite geometric series is

S=\frac{a_1}{1-r} where r is between -1 and 1 and r is the common ratio, and a_1 is the first term of the series.

So let's plug in:

S=\frac{0.3}{1-0.1}

S=\frac{0.3}{0.9}

S=\frac{3}{9} I multiplied bottom and top by 10.

S=\frac{1}{3} I divided top and bottom by 3.

The sum is 1/3.

8 0
3 years ago
A jet travels 2301 miles against the wind in 3 hours and 2811 miles with the wind in the same amount of time. What is the rate o
astraxan [27]

Answer:

The rate of the jet in still air is 852 miles per hour. The rate of the wind is 85 miles per hour.

Step-by-step explanation:

Let suppose that jet travels uniformly, that is, at constant speed, the expressions for its travels against the wind and with the wind are, respectively:

Against the wind

v -u = \frac{\Delta x_{1}}{\Delta t_{1}}

With the wind

v +u = \frac{\Delta x_{2}}{\Delta t_{2}}

Where:

v - Speed of the jet in still air, measured in miles per hour.

u - Speed of wind, measured in miles per hour.

\Delta x_{1}, \Delta x_{2} - Distances travelled by jet against the wind and with the wind, measured in miles.

\Delta t_{1}, \Delta t_{2} - Times against the wind and with the wind, measured in hours.

By adding both expressions:

2\cdot v = \frac{\Delta x_{1}}{\Delta t_{1}}+\frac{\Delta x_{2}}{\Delta t_{2}}

v = \frac{1}{2}\cdot \left(\frac{\Delta x_{1}}{\Delta t_{1}} + \frac{\Delta x_{2}}{\Delta t_{2}} \right)

Given that \Delta x_{1} = 2301\,mi, \Delta t_{1} = 3\,h, \Delta x_{2} = 2811\,mi and \Delta t_{2} = 3\,h, the speed of the jet is:

v = \frac{1}{2}\cdot \left(\frac{2301\,mi}{3\,h}+\frac{2811\,mi}{3\,h}  \right)

v = 852\,\frac{mi}{h}

The rate of the jet in still air is 852 miles per hour.

Lastly, the rate of the wind is:

u = \frac{\Delta x_{2}}{\Delta t_{2}}-v

u = \frac{2811\,mi}{3\,h}-852\,\frac{mi}{h}

u = 85\,\frac{mi}{h}

The rate of the wind is 85 miles per hour.

 

5 0
3 years ago
21. 2n= 53 <br><br> Explanation of the division please, and how you got the answer
Ksju [112]

Answer:

2n= 53

and you divide both sides by 2

2n/2 =53/2

2 divided by 2 is 1 and 53 divided 2 is 26.5

n= 26.5

5 0
3 years ago
1 plus 1 plus 0 plus 0
Romashka [77]
1 + 1 + 0 + 0 = 2 + 0 = 2

 Answer is 2. 
3 0
3 years ago
Read 2 more answers
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