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zhenek [66]
3 years ago
7

Solve for n

Mathematics
2 answers:
slava [35]3 years ago
8 0
You put 63 over 9, basically dividing 63 by 9 which gives you 7, so n = 7
Luden [163]3 years ago
3 0
Well, what you need to figure out is what times 9 is 63. That would be 7. So n=7 :)
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The difference of twenty-one and eight times a number n is thiry-five
nalin [4]

Answer:

n=7

Step-by-step explanation:

difference means subtraction so:

8n - 21= 35

8n=35+21

8n= 56

n= 56÷8

n=7

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3 years ago
What is the surface area of the pyramid? 12ft 10ft 10ft
jonny [76]

Answer:

2h x (l+b)

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3 0
3 years ago
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Unsure of what i need to do for question 1 and 2
AfilCa [17]

Answer:

f(1)=0; f(0)= -2; f(-1)=(-4); f(2)=2

Step-by-step explanation:

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For 5 and 6: when they say f(x) = some value, this is the y value. So look at the graph: when y = 4, you can see that x = 3. When y = -6, you can see that x= -2.

8 0
3 years ago
There are 3 times as many pears are oranges. If a group of children receive 5 oranges each,there will be no left over.If the sam
lozanna [386]

There are 15 oranges

<em><u>Solution:</u></em>

Let "x" be the number of oranges

Let "y" be the number of pears

Let "c" be the number of children

<em><u>There are 3 times as many pears are oranges</u></em>

Number of pears = 3 times the number of oranges

y = 3x -------- eqn 1

<u><em>If a group of children receive 5 oranges each, there will be no left over</em></u>

So, "c" children receives 5 oranges each, there will be no left over

number of oranges = 5(number of children)

x = 5c ------- eqn 2

<em><u>If the same group of children receive 8 oranges each, there will be 21 pears left over</u></em>

number of pears = 8 oranges(number of children) + 21

y = 8c + 21

<em><u>Substitute eqn 1</u></em>

3x = 8c + 21 ---- eqn 3

<em><u>Substitute eqn 2</u></em>

3(5c) = 8c + 21

15c - 8c = 21

7c = 21

c = 3

<em><u>Substitute c = 3 in eqn 2</u></em>

x = 5(3)

x = 15

Thus there are 15 oranges

6 0
3 years ago
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Vadim26 [7]
Perpendicular has slope that multiplies to -1
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y=x+b
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y=x+5 is equation
not listed, but the choices are all wrong
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