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Alexxandr [17]
3 years ago
8

Use the rules of significant figures to answer the following question: 22.674 • 15.05

Mathematics
2 answers:
olga_2 [115]3 years ago
6 0
I think it is b. 341.24
aleksklad [387]3 years ago
6 0
D. 341.2437 All you had to do was use a calculator and if you aren't allowed to then match up the decimals. GOOD LUCK!!
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The price of apples is $3.60 for 3 pounds write the price as a unit rate
Finger [1]

Take the total and divide by the amount to get answer.

3.60 /3 = $1.20 per pound

4 0
3 years ago
What is the value of h?<br> h = 20<br> h=35<br> h = 70<br> (2h)<br> (2h)
postnew [5]

Answer:

-7/2 or -3.5

Step-by-step explanation:

h = 20 = h = 35  = h = 70  (2h)  (2h)

19h = 35h = 70(2h)(2h)

16h = 70(2h)(2h)

-70 = 20h

-7/2 = h

-3.5 = h

7 0
3 years ago
Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15
Digiron [165]

\huge \boxed{\mathfrak{Question} \downarrow}

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{array}  { l  }  { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.

  • To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x-5y=-13, \: 3x+4y=15

  • Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

2x-5y=-13

  • Add 5y to both sides of the equation.

2x=5y-13

  • Divide both sides by 2.

x=\frac{1}{2}\left(5y-13\right)  \\

  • Multiply \frac{1}{2}\\ times 5y - 13.

x=\frac{5}{2}y-\frac{13}{2}  \\

  • Substitute \frac{5y-13}{2}\\ for x in the other equation, 3x + 4y = 15.

3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15  \\

  • Multiply 3 times \frac{5y-13}{2}\\.

\frac{15}{2}y-\frac{39}{2}+4y=15  \\

  • Add \frac{15y}{2} \\ to 4y.

\frac{23}{2}y-\frac{39}{2}=15  \\

  • Add \frac{39}{2}\\ to both sides of the equation.

\frac{23}{2}y=\frac{69}{2}  \\

  • Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{ \underline{ \sf \: y=3 }}

  • Substitute 3 for y in x=\frac{5}{2}y-\frac{13}{2}\\. Because the resulting equation contains only one variable, you can solve for x directly.

x=\frac{5}{2}\times 3-\frac{13}{2}  \\

  • Multiply 5/2 times 3.

x=\frac{15-13}{2}  \\

  • Add -\frac{13}{2}\\ to \frac{15}{2}\\ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

\large\underline{ \underline{ \sf \: x=1 }}

  • The system is now solved. The value of x & y will be 1 & 3 respectively.

\huge\boxed{  \boxed{\bf \: x=1, \: y=3 }}

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find two numbers that equal 11,000 when added together, but also equal 3,000 when subtracted from each other
amm1812

Answer:

4000 and 7000

Step-by-step explanation:

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2 years ago
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