Answer:
a) 
Step-by-step explanation:
x + 2 = 3x + 6
-3x - 3x
___________
−2x + 2 = 6
- 2 - 2
_________
4 = −2x
_ ___
−2 −2
[Plug this back into both equations above to get the y-coordinate of 0]; 
I am joyous to assist you anytime.
Answer: Length = 15 meters
Width = 2 meters
Step-by-step explanation:
Perimeter of a rectangle = 2l + 2w
Area of a rectangle = l × w
where l = length
w = width
Therefore,
2l + 2w = 34 ...... i
l × w = 30 ........ ii
From equation i
2l + 2w = 34
Divide through by 2.
l + w = 17 ...... iii
Then, l = 17 - w ........ iv
Put equation iv into ii
l × w = 30
(17 - w) × w = 30
17w - w² = 30
w² - 17w + 30 = 0
w² - 15w - 2w + 30 = 0
w(w - 15) - 2(w - 15) = 0
(w - 2) = 0
w = 0 + 2 = 2
w - 15 = 0
w = 0 + 15 = 15
Length = 15 meters
Width = 2 meters
Hello there.
<span>How many solutions does the system of equations have y=5x+7 and 3y-15x=18
</span><span>B two
</span>
I think the answer to (Y) may be 40 cubic units
Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
