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77julia77 [94]
3 years ago
15

What is 47/15 rounded to the nearest hundredth?

Mathematics
2 answers:
inessss [21]3 years ago
7 0

Answer:4

Step-by-step explanation:

It’s would be 4 because 47/15=3.23333 and because you said to the nearest hundred than it would be rounded to 4

sergejj [24]3 years ago
3 0

Answer:

3.13

Step-by-step explanation:

47/15

47 ÷ 15 = 3.1333333...

The answer is a terminating decimal, so we need to round it. In this case, we need to round to the nearest hundredth.

3.133333... = 3.13

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8.75 x 10 ^3 in standard form
Sveta_85 [38]

Answer:

8.75×10^3

Step-by-step explanation:

here is the answer

6 0
3 years ago
Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar
oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 18 means that N = 18

9 are carrying nuclear weapons, which means that k = 9

9 are destroyed, which means that n = 9

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021

P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0
3 years ago
A student who is 5 ft 6 in. tall measured shadows
irakobra [83]

Answer:

lunar model

there really isnt anything to explain

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Which is the simplified form of the expression 12n-1/2(6n-4)
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The simplified for is 9n+2
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If 12x+8 is less than 6,what is the value of 8x​
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