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Alecsey [184]
3 years ago
11

Can someone plz help thxs

Mathematics
1 answer:
emmasim [6.3K]3 years ago
4 0
Sheeeeeeessssssshhhhhhhh
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Write the slope-intercept form of the equation of the line through the point (-1,-4) with the slope of 6.
igomit [66]

Answer:

y-y1=m(x-x1)

y+4=6(x+1)

y=6x+2

4 0
3 years ago
In which figure is point G an orthocenter ?
Papessa [141]
None of the above.
The orthocenter is the point where the three altitudes meet. An altitude is the line from one vertex perpendicular to the opposite side. 
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3 years ago
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Suppose an unknown radioactive substance produces 8000 counts per minute on a Geiger counter at a certain time, and only 500 cou
mariarad [96]

Answer:

The half-life of the radioactive substance is of 3.25 days.

Step-by-step explanation:

The amount of radioactive substance is proportional to the number of counts per minute:

This means that the amount is given by the following differential equation:

\frac{dQ}{dt} = -kQ

In which k is the decay rate.

The solution is:

Q(t) = Q(0)e^{-kt}

In which Q(0) is the initial amount:

8000 counts per minute on a Geiger counter at a certain time

This means that Q(0) = 8000

500 counts per minute 13 days later.

This means that Q(13) = 500. We use this to find k.

Q(t) = Q(0)e^{-kt}

500 = 8000e^{-13k}

e^{-13k} = \frac{500}{8000}

\ln{e^{-13k}} = \ln{\frac{500}{8000}}

-13k = \ln{\frac{500}{8000}}

k = -\frac{\ln{\frac{500}{8000}}}{13}

k = 0.2133

So

Q(t) = Q(0)e^{-0.2133t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.2133t}

0.5Q(0) = Q(0)e^{-0.2133t}

e^{-0.2133t} = 0.5

\ln{e^{-0.2133t}} = \ln{0.5}

-0.2133t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.2133}

t = 3.25

The half-life of the radioactive substance is of 3.25 days.

7 0
3 years ago
A scientist invents a car that can travel for many hours without stopping for fuel. The car travels around a track at 51 miles a
EleoNora [17]
Well 51 per hour and there is 24 hours so you just multiply the two together. Which you would get get 1,224 Miles
4 0
3 years ago
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Which is the value of the discriminant for the quadratic equation 0=x+2+x^2​
solong [7]
0 = x + 2 + x^2
x^2 + x + 2 = 0
a = 1, b = 1, c = 2

discriminant = b^2 - 4ac = 1^2 - (4 x 1 x 2) = 1 - 8 = -7
7 0
4 years ago
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