Y-2=3x+3
Then add two
So y=3x+5
Hope this helps sorry if wrong
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
Answer:28.26
Step-by-step explanation:9 x 3.14
Sinα=h/L where h=height, L=string length...
h=Lsinα so
h(25°)=50sin25≈21.1ft
h(45°)=50sin45≈35.4ft
Answer:

Step-by-step explanation:
You would do y2-y1 over x2-x1. In your equation, this would be -15-0 over -11-3, giving you -15 over -14