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lapo4ka [179]
4 years ago
11

1. Think about the various ways in which you have seen hackers portrayed in popular media over the past few years. Are they hero

ic characters or dangerous criminals? Do the representations conform to any of the realities of the hacker subculture, or do they simply further stereotypes about hackers as a whole?
Computers and Technology
1 answer:
Eva8 [605]4 years ago
3 0
They are definitely not heroic characters, so you can rule that out. Definitely dangerous criminals. If you need me to help further I can. Is that a question or an essay?
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How can photography allow us to view the world around us in different ways?
Ymorist [56]
It captures a single moment that one might not see with a naked eye. It shows the beauty and the essence of simple things in one exact moment. And it allows the viewer to take more time to reflect on what is captured and really find meaning within it.
6 0
4 years ago
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What is the difference between above ground mining and underground mining?
neonofarm [45]
If this is in reference to diamond mining then above ground would be panning while below ground would be the actual mining into the soil. 
6 0
3 years ago
Design the program in the following way:
natali 33 [55]

Answer:

d = {}

while True:

   name = input("Enter the name of the boat (Press Enter or q to stop): ")

   if name == "" or name == "q":

       break

   time = int(input("Enter the time (in seconds): "))

   d[name] = time

winner_name = min(d, key=d.get)

winner_time = min(d.values())

average_time = sum(d.values()) / len(d.values())

slowest_boat = max(d, key=d.get)

slowest_time = max(d.values())

print(f"Winner name: {winner_name} and its time: {winner_time}")

print(f"Average time: {average_time}")

print(f"Slowest boat: {slowest_boat} and its time: {slowest_time}")

Explanation:

*The code is in Python.

Create an empty map(dictionary) to hold the values

Create a while loop. Inside the loop:

Ask the user to enter the name of the boat. Check if the user presses Enter or q, using if and break

Ask the user to enter the time

Insert these values as key-value pair to the map

When the loop is done:

Find the winner_name, the min() function finds the minimum value in a list. In this case, the key=d.get creates a list of the values in the map. The min(d, key=d.get) returns the key of the minimum value

Find the winner_time, min(d.values()) returns the minimum time in our map

Find the average time, the sum() function, returns the sum of the values in a list. In this case, sums all the values in the map. The len() function finds the count of the values. If we divide the sum of times entered by the count of the times entered, we get the average time

Find the slowest_time, the max() function returns the max of the value in a list. In this case, the maximum value is the slowest time

Print the results

5 0
3 years ago
Will creates an entry in his calendar and marks it as an all-day instance. Which item has he created?
Hatshy [7]

Answer:

The answer u looking for is event

5 0
3 years ago
Read 2 more answers
An array of integers named parkingTickets has been declared and initialized to the number of parking tickets given out by the ci
Sedaia [141]

Answer:

Following code will store the largest value in array parkingTickets in the variable mostTickets

mostTickets = parkingTickets[0];

for(int k = 0; k<parkingTickets.length; k++)

{

if(parkingTickets[i]>mostTickets)

{

 mostTickets = parkingTickets[i];

}

}

Explanation:

In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.

Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.

If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.

This process is repeated for all elements in array.

Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.  

6 0
3 years ago
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