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Olenka [21]
3 years ago
9

When installing conduit for a mast service, what type of conduit should you use?

Computers and Technology
2 answers:
lesya692 [45]3 years ago
7 0
The answer is (b) Rigid-metal

If you are installing a conduit for a mast service, the type of conduit to be used should be a rigid metal type. Among the three types of steel conduit, the most preferable to install is the rigid metal type instead of an intermediate metal conduit and electrical metallic tubing. Rigid metal conduit is a ferrous metal.
Arturiano [62]3 years ago
3 0

The answer is Rigid-metal

Rigid metal conduit is heavy-duty galvanized steel tubing that is typically used outdoors to provide protection from damage. It provides structural support for electrical panels, cables, and mast. Another important advantage of zinc- based rigid metal conduit is that it has no temperature limitations. IMC and EMC are lighter-weight versions of rigid metal conduits and can be bent easily using conduit benders. These two metals are not the best for mast installations.

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Calculate the total number of bits transferred if 200 pages of ASCII data are sent using asynchronous serial data transfer. Assu
Mumz [18]

Answer:

4000000 bits

Explanation:

The serial port configuration in asynchronous mode actually assumes a data size of 8bits, 1 start bit, no parity and 1 stop bit.

Therefore 8+1+1 = 10 bits.

This means that for every eight bits of data, ten bits are sent over the serial link — one start bit, the eight data bits, and the one stop bit)

We also know that there are 200 pages of ASCII data using asynchronous serial data transfer and each page has 80*25 of text characters.

Therefore the total number of bits transferred:

200*80*25*10 = 4000000 bits

5 0
3 years ago
2. What's the keyboard command that will allow you to "copy" text?
nataly862011 [7]

The answer is Ctrl c

8 0
3 years ago
Read 2 more answers
Create a SavingsAccount class. Use a static data member annualInterestRate to store the annual interest rate for each of the sav
andrew-mc [135]

Answer:

see explaination

Explanation:

SavingsAccount.h

#pragma once

#ifndef SAVINGS_H

#define SAVINGS_H

//SavingsAccount class declaration

class SavingsAccount

{

//declare data members

private:

//set annualInterestRate to 0.0 default value

static double annualInterestRate;

double savingsBalance;

public:

//set the balance

void setBalance(double);

//modify interest rates

static void modifyInterestRate(double);

//retruns total balance with interest

double calculateMonthInt();

};

#endif

SavingsAccount.cpp

//include required header files

#include<iostream>

#include"SavingsAccount.h"

using namespace std;

//set the annualInterestRate to 0

double SavingsAccount::annualInterestRate = 0;

//static funtion modify interest rate

void SavingsAccount::modifyInterestRate(double iRate)

{

annualInterestRate = iRate;

}

//set the balance

void SavingsAccount::setBalance(double bal)

{

savingsBalance = bal;

}

//calculating savings balance with monthly interest

double SavingsAccount::calculateMonthInt()

{

double monthInt = 0;

monthInt += savingsBalance*annualInterestRate / 12;

return savingsBalance += monthInt;

}

DriverProgram.cpp

//include required header files

#include<iostream>

#include "SavingsAccount.h"

using namespace std;

//main methods

int main()

{

//delcare class objects

SavingsAccount saver1, saver2;

//setter functions of balance

saver1.setBalance(2000.00);

saver2.setBalance(3000.00);

//Setting annual interset 0.03 to static variable

saver1.modifyInterestRate(0.03);

//finding the balance in saver1 and saver2 account

cout << "Balance of saver1 and saver2 on 3% interest Rate\n";

cout << "--------------------------------------------------\n";

cout << "Balance of saver1 = " << saver1.calculateMonthInt()

<< endl;

cout << "Balance of saver2 = " << saver2.calculateMonthInt()

<< endl << endl;

//Setting annual interset 0.04 to static variable

saver1.modifyInterestRate(0.04);

cout << "Balance of saver1 and saver2 on 4% interest Rate\n";

cout << "---------------------------------------------------\n";

cout << "New Balance of saver1 = " << saver1.calculateMonthInt() << endl;

cout << "New Balance of saver2 = " << saver2.calculateMonthInt() << endl<<endl;

return 0;

}

4 0
3 years ago
Suppose that the first goal in a GP problem is to make 3 X1 + 4 X2 approximately equal to 36. Using the deviational variables d1
Scrat [10]

Answer:

d. d1− = 10, d1+ = 0

Explanation:

Given

3X1 + 4X2 +d1− − d1+ = 36

X1 = 6

X2 = 2

Required

Possible values of d1- and d1+

We have:

3X1 + 4X2 +d1− − d1+ = 36

Substitute values for X1 and X2

3 *6 + 4 * 2 + d1- - d1+ = 36

18 + 8 + d1- - d1+ = 36

Collect like terms

d1- - d1+ = 36 - 18 - 8

d1- - d1+ = 10

For the above equation to be true, the following inequality must be true

d1- > d1+

Hence,

(d) is correct

Because:

10 > 0

3 0
3 years ago
What is the correct order of precedence of the mathematical operators?
LenaWriter [7]
A common technique for remembering the order<span> of </span>operations<span> is the abbreviation "PEMDAS", which is turned into the phrase "Please Excuse My Dear Aunt Sally". It stands for "Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction".</span>
7 0
3 years ago
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