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elena-s [515]
3 years ago
11

CSNET Stand for in a computer

Computers and Technology
1 answer:
laiz [17]3 years ago
6 0

Answer:

computer,science,network

Explanation:

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Using the FAFSA form , you can for apply for what
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apply for financial aid for college or grad school.

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Natalie enjoys talking to people and helping them with their problems. Her friends always tell her that she’s a good listener. B
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C and D

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A service provider recently upgraded one of the storage clusters that houses non-confidential data for clients. The storage prov
VARVARA [1.3K]

Answer:

<em>C. Purging</em>

<em></em>

Explanation:

<em>Data Purging in computer storage is a process that permanently erases and remove data from a storage space</em>.  Data deleting only removes the shortcut to the data but does not remove the data permanently, and can be easily recovered by an expert. <em>Data purging removes data permanently and also frees up the storage or memory space for other uses.</em> Data purging is relatively inexpensive and can be achieved with some special software tool.

Since the storage provider wants the hard drive back in working condition, data purging is the best option.

3 0
3 years ago
Write a program that reads a string consisting of a positive integer or a positive decimal number and converts the number to the
jeka94

Answer:

#include <iostream>

#include <string>

#include <stack>

#include <math.h>

using namespace std;

int main() {

  string s;

  double n=0;

  int position=0;  

  stack<int> wholeNumbers;

  cout<<"Enter a decimal number:";

  cin>>s;

  string::iterator counter = s.begin();

  while(*counter!='.' && counter!=s.end()){

      wholeNumbers.push(*counter-48);

      counter++;

      position=position+1;

     

  }

  for(int i=0;i<position;i++){

      n=n+(wholeNumbers.top()*pow(10,i));

      wholeNumbers.pop();

  }

  position=-1;

  if(counter!=s.end()){

      counter++;

  }

  while(counter!=s.end()){

      n=n+((*counter-48)*pow(10,position));

      position=position-1;

      counter++;      

  }

  cout<<n;

}

Explanation:

  • Inside the while loop, push the push a number to the wholeNumbers stack by subtracting it with 48.
  • Increment the counter and position variable by 1 inside the while loop.
  • Count the number of digit, push each digit to top of stack and find the end of the number,
  • Run a for loop up to the value of position variable and pop a value from the wholeNumbers stack.
5 0
4 years ago
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