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uranmaximum [27]
3 years ago
6

Suppose an investment of $2000 doubles in value every 8 years. How much is the investment worth after 24 years? After 32 years?

Mathematics
1 answer:
guapka [62]3 years ago
8 0
24 years = $16,000
33 years = $32,000

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1/x^-2 x=7 yeet yeet
Yanka [14]

Answer:

49

Step-by-step explanation:

x = 7

1 / x^-2

= x^2

= 7^2

= 49

8 0
3 years ago
The length of the top of a table is 55 m greater than the width. the area is 8484 msquared2. find the dimensions of the table.
Oksana_A [137]
You have to do similar calculations you use in algebra. This is how I get the answer;
First I draw out the algebraic formula 55m • X = 8,484 m (meters) 2 (squared). Then I switch the sign from multiplication to division and switch put numbers 55 and 8,484 in different places and change it to your new formula 8,484/(divided) 55 =X. Then you do the math of 8,484 divided by 55 and get an answer of 154.254545. But you can just leave it at the first 2 digits on the right side of the decimal by rounding 4 down and leaving it at an answer of ~~(<This is your answer after being put together with these tips (you always right your final answer using your formula and plugging in the number that we got from dividing 8,484 by 55;

Final answer ( if they wanted it included in a formula); 8,484/55=X let X=~~154.25

Final answer (if they wanted it as one final number as you answer); ~~154.25

*Hope these tips helped you with this mathematical problem :)
4 0
3 years ago
Multiply 1/10x17/18 pls help I'll give u brainlest​
Andrej [43]

Calculate :

\frac{1}{10}  \times  \frac{17}{18}  =  \frac{1 \times 17}{10 \times 18}  =  \frac{17}{180}

4 0
3 years ago
Read 2 more answers
3The frequency (in Hz) of a vibrating violin string is given by f = 1 2L s T rho where L is the length of the string (in meters)
bagirrra123 [75]

Answer:

(i) \dfrac{df}{dL}=-\dfrac{1}{2L^2}\sqrt{\dfrac{T}{\rho}}

(ii) \dfrac{df}{dT}=\dfrac{1}{4L\sqrt{T\rho}}

(iii) \dfrac{df}{d\rho}=-\dfrac{\sqrt{T}}{4L\rho^{-\frac{3}{2}}}}

Step-by-step explanation:

Let as consider the frequency (in Hz) of a vibrating violin string is given by

f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\rho}}

(i)

Differentiate f with respect L (assuming T and rho are constants).

\dfrac{df}{dL}=\dfrac{d}{dL}\dfrac{1}{2L}\sqrt{\dfrac{T}{\rho}}

Taking out constant terms.

\dfrac{df}{dL}=\dfrac{1}{2}\sqrt{\dfrac{T}{\rho}}\dfrac{d}{dL}\dfrac{1}{L}

\dfrac{df}{dL}=\dfrac{1}{2}\sqrt{\dfrac{T}{\rho}}(-\dfrac{1}{L^2})

\dfrac{df}{dL}=-\dfrac{1}{2L^2}\sqrt{\dfrac{T}{\rho}}

(ii)

Differentiate f with respect T (assuming L and rho are constants).

\dfrac{df}{dT}=\dfrac{d}{dT}\dfrac{1}{2L}\sqrt{\dfrac{T}{\rho}}

Taking out constant terms.

\dfrac{df}{dT}=\dfrac{1}{2L}\sqrt{\dfrac{1}{\rho}}\dfrac{d}{dT}\sqrt{T}}

\dfrac{df}{dT}=\dfrac{1}{2L}\sqrt{\dfrac{1}{\rho}}(\dfrac{1}{2\sqrt{T}})

\dfrac{df}{dT}=\dfrac{1}{4L\sqrt{T\rho}}

(iii)

Differentiate f with respect rho (assuming L and T are constants).

\dfrac{df}{d\rho}=\dfrac{d}{d\rho}\dfrac{1}{2L}\sqrt{\dfrac{T}{\rho}}

Taking out constant terms.

\dfrac{df}{d\rho}=\dfrac{\sqrt{T}}{2L}\dfrac{d}{d\rho}(\rho)^{-\frac{1}{2}}}

\dfrac{df}{d\rho}=\dfrac{\sqrt{T}}{2L}(-\dfrac{1}{2}(\rho)^{-\frac{3}{2}}})

\dfrac{df}{d\rho}=-\dfrac{\sqrt{T}}{4L\rho^{-\frac{3}{2}}}}

4 0
3 years ago
Giving away 30 points, have a good day​
weqwewe [10]

Answer:

For real???

Step-by-step explanation:

Tysm!! <3 you deserve so much!

4 0
3 years ago
Read 2 more answers
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