Answer:
a) x = 1225.68
b) x = 1081.76
c) 1109.28 < x < 1198.72
Step-by-step explanation:
Given:
- Th random variable X for steer weight follows a normal distribution:
X~ N( 1154 , 86 )
Find:
a) the highest 10% of the weights?
b) the lowest 20% of the weights?
c) the middle 40% of the weights?
Solution:
a)
We will compute the corresponding Z-value for highest cut off 10%:
Z @ 0.10 = 1.28
Z = (x-u) / sd
Where,
u: Mean of the distribution.
s.d: Standard deviation of the distribution.
1.28 = (x - 1154) / 86
x = 1.28*86 + 1154
x = 1225.68
b)
We will compute the corresponding Z-value for lowest cut off 20%:
-Z @ 0.20 = -0.84
Z = (x-u) / sd
-0.84 = (x - 1154) / 86
x = -0.84*86 + 1154
x = 1081.76
c)
We will compute the corresponding Z-value for middle cut off 40%:
Z @ 0.3 = -0.52
Z @ 0.7 = 0.52
[email protected] < x < [email protected]
-.52*86 + 1154 < x < 0.52*86 + 1154
1109.28 < x < 1198.72
Answer:
So we have a ratio which you have specified 13:52. So we just need to get the same ratio for 13. 32/52 is how we get 32 from multiplying by 52. So now we just need to multiply it for 13 also'
13*32/52 = 8. Therefore the answer to this is 8
<h2 /><h2><u>
8 is answer</u></h2>
<span>The logic in the sequence is --> +2, +2, +3, +3, +4, +4, +5, +5, +6, +6 and so on...
So, </span><span>the next number in the sequence would be 24+5 = 29
So, the answer is --> c.29
</span>
Answer:
16°
Step-by-step explanation:
2x° + 6° = 38°
x° = (38°- 6°)÷2=16°
