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frez [133]
3 years ago
5

 An expandable cone-shaped funnel consists of two sections as shown.

Mathematics
1 answer:
katen-ka-za [31]3 years ago
7 0
The bottom section of the funnel is in the shape of cone with radius = 6 cm and height = 8 cm

The volume of a cone is given by \frac{1}{3} \pi r^{2} h
V= \frac{1}{3} \pi ( 3^{2} )(8)=24\pi

The volume of the top part of the cone, called frustum, is the volume of big cone subtract volume of smaller cone

Volume of big cone =  \frac{1}{3} \pi ( 6^{2} )(16)=192 \pi

Volume of frustum = 192 \pi -24 \pi =168 \pi

We can leave the answer as an exact answer (168 \pi) or as decimal (527.79 rounded to two decimal places)
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the average monthly precipitation for dallas for oct, nov, and dec is 3.47 in. If 2.88 in. falls in oct and 3.13 in. falls in no
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3 years ago
JL = 28,<br> KL= 5x + 6, and<br> JK = 3x + 6,
Alexeev081 [22]

Answer:

KL = 16

Step-by-step explanation:

For this problem, JL is the sum of KL and JK.  So we can say this:

JK + KL = JL

( 3x + 6 ) + ( 5x + 6 ) = 28

8x + 12 = 28

8x = 16

x = 2

So, now we can find KL:

5x + 6 = ?

5(2) + 6 = ?

10 + 6 = ?

16 = ?

So the length of KL is 16.

Cheers.

7 0
4 years ago
You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard devia
gtnhenbr [62]

Answer:

n=(\frac{2.58(58.2)}{1})^2 =22546.82 \approx 22547

So the answer for this case would be n=22547 rounded up to the nearest integer

Step-by-step explanation:

Let's define some notation

\bar X represent the sample mean

\mu population mean (variable of interest)

\sigma=58.2 represent the population standard deviation

n represent the sample size  

ME =1 represent the margin of error desire

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =+1 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance would be \alpha=0.01 and the critical value z_{\alpha/2}=2.58, replacing into formula (b) we got:

n=(\frac{2.58(58.2)}{1})^2 =22546.82 \approx 22547

So the answer for this case would be n=22547 rounded up to the nearest integer

3 0
3 years ago
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