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3 years ago

2 times what equals 120

Mathematics

1 answer:

4vir4ik [10]3 years ago

7 0

Answer:

Step-by-step explanation:

Simple, just divide 120 by 2.

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What is the slope of the line that passes through the points (1, -2) and (3, -5)?

Ksivusya [100]

Slope of the line is -3/2

Step-by-step explanation:

Step 1: Given points are (1, -2) and (3, -5)
Step 2: Equation for slope, m = (y2 - y1)/(x2 - x1)

⇒ m = (-5 - -2)/(3 - 1) = -3/2

4 0

3 years ago

Image is down below :)

zhuklara [117]

-3, 1 is the answer because the spot is on the -3 and in the first low with the Y-axis and stuff .

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3 years ago

Read 2 more answers

Each of the letters of the word ALABAMA are written on a piece of paper and then

Kruka [31]

Answer:

3/7

Step-by-step explanation:

There are 7 letters in ALABAMA. And there are 4 A's in ALABAMA. So if you're trying to not get an A then you would subtract 4 from 7. Which you would get 3/7 of the letters in ALABAMA are not A.

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2 years ago

The highway fuel economy of a 2016 Lexus RX 350 FWD 6-cylinder 3.5-L automatic 5-speed using premium fuel is a normally distribu

Elodia [21]

Answer:

a) Standard error = 0.5

b) 99% Confidence interval: (19.2125,21.7875)

Step-by-step explanation:

We are given the following in the question:

Population mean = 20.50 mpg

Sample standard deviation = 3.00 mpg

Sample size , n = 36

Standard Error =

$=\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = 0.5$

99% Confidence interval:

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.01} = \pm 2.575$

$20.50 \pm 2.575(\displaystyle\frac{3}{\sqrt{36}})= 20.50 \pm 1.2875 = (19.2125,21.7875)$

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2 years ago

The height, h, in feet of a ball above the ground is given by h = −16t2 + 64t + 80, where t is the time in seconds. How long doe

Gwar [14]

Answer:

t = 5 seconds

Step-by-step explanation:

It is given that, the height h, in feet of a ball above the ground is given by :

$h=-16t^2+64t+80$

Where t is in seconds

We need to find how long does it take the ball to hit the ground? When it hits the ground, its height will be equal to 0. So,

$-16t^2+64t+80=0\\\\t=\dfrac{-64\pm \sqrt{(64)^2-4\times (-16)(80)} }{2\times -16}\\\\t=\dfrac{-64+ \sqrt{(64)^2-4\times (-16)(80)} }{2\times -16},\dfrac{-64-\sqrt{(64)^2-4\times (-16)(80)} }{2\times -16}\\\\t=-1\ s\ \text{and}\ t=5\ s$

Neglecting negative time.

It means ball will take 5 seconds to hit the ground.

3 0

2 years ago