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julia-pushkina [17]
3 years ago
14

Find the measure of c. A. 10 B. 280 C. 100 D. 140

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
3 0

Answer:

63°

Step-by-step explanation:

a = 27°

b = 180° - (a + 27°)

b = 180° - (27° + 27°)

b = 180° - 54°

b = 126°

By inscribed angle theorem:

c = 1/2 b = 1/2 * 126°

c = 63°

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Police Chase: A speeder traveling 40 miles per hour (in a 25 mph zone) passes a stopped police car which immediately takes off a
zubka84 [21]

Answer:

a. 18.34 s b. 327.92 m

Step-by-step explanation:

a. How long before the police car catches the speeder who continued traveling at 40 miles/hour

The acceleration of the car a in 10 s from 0 to 55 mi/h is a = (v - u)/t where u = initial velocity = 0 m/s, v = final velocity = 55 mi/h = 55 × 1609 m/3600 s = 24.58 m/s and t = time = 10 s.

So, a =  (v - u)/t =  (24.58 m/s - 0 m/s)/10 s = 24.58 m/s ÷ 10 s = 2.458 m/s².

The distance moved by the police car in 10 s is gotten from

s = ut + 1/2at² where u = initial velocity of police car = 0 m/s, a = acceleration = 2.458 m/s² and t = time = 10 s.

s = 0 m/s × 10 s + 1/2 × 2.458 m/s² (10)²

s = 0 m + 1/2 × 2.458 m/s² × 100 s²

s = 122.9 m

The distance moved when the police car is driving at 55 mi/h is s' = 24.58 t where t = driving time after attaining 55 mi/h

The total distance moved by the police car is thus S = s + s' = 122.9 + 24.58t

The total distance moved by the speeder is S' = 40t' mi = (40 × 1609 m/3600 s)t' =  17.88t' m where t' = time taken for police to catch up with speeder.

Since both distances are the same,

S' = S

17.88t' = 122.9 + 24.58t

Also, the time  taken for the police car to catch up with the speeder, t' = time taken for car to accelerate to 55 mi/h + rest of time taken for police car to catch up with speed, t

t' = 10 + t

So, substituting t' into the equation, we have

17.88t' = 122.9 + 24.58t

17.88(10 + t) = 122.9 + 24.58t

178.8 + 17.88t = 122.9 + 24.58t

17.88t - 24.58t = 122.9 - 178.8

-6.7t = -55.9

t = -55.9/-6.7

t = 8.34 s

So, t' = 10 + t

t' = 10 + 8.34

t' = 18.34 s

So, it will take 18.34 s before the police car catches the speeder who continued traveling at 40 miles/hour

b. how far before the police car catches the speeder who continued traveling at 40 miles/hour

Since the distance moved by the police car also equals the distance moved by the speeder, how far the police car will move before he catches the speeder is given by S' = 17.88t' = 17.88 × 18.34 s = 327.92 m

4 0
2 years ago
PLEASEE HELPP<br> FIND M A 19<br> B 22<br> C 23<br> D 161
Likurg_2 [28]
M∠ABC=180°

7x+x-4 = 180
8x = 180+4
8x=184
x=184:8
x=23

∠DBС = x-4 = 23-4 = 19°

Answer: 19°.
7 0
3 years ago
Read 2 more answers
ANSWER ASAP PLS
katrin [286]

Answer:

21/6 can be divided by 3, so 7/2

7/2 cannot be divided into any more shared factors, so final answer is 7:2.

4 0
2 years ago
Can someone help me! Please
likoan [24]

Answer:

4c - 2

Step-by-step explanation:

Add up all the terms to find the perimeter.

2c + 2(c - 1)

2c + 2c - 2

4c - 2

Therefore, the perimeter is 4c - 2.

5 0
3 years ago
at cheng's bike rentals, it costs $21 to rent a bike for 6 hours. how many dollars does it cost per hour of bike use?
Vlada [557]
Rent for 6 hours = 21
rent for a hour = 21/6
                        = $3.5
4 0
2 years ago
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