Question

PLZ ANSWER ASAP!!!!

Answer 1

$f(x) = 6x - 4 + x^2$

We complete the square to get vertex form.

$f(x) = x^2 + 6x - 4$

$f(x) = x^2 +6x + 9-9- 4$

$f(x) = (x+3)^2-13$

The vertex form of the function is f(x) = (x – 2)2 + 2.

Nope.

The vertex of the function is (–3, –13).

Yes, that's easily seen from the vertex form we got.

 The axis of symmetry for the function is x = 3.

Nope, x = -3 is the symmetry axis.

 The graph increases over the interval (–3, infinity).

That's true; the minimum is at the vertex when the squared term is zero and it increases both ways from there.

The function does not cross the x-axis.

No, it does cross; its minimum is -13 and it goes up from there.