Answer:
would not be helpful to anser nowww... sory!
Step-by-step explanation:
Answer:
c.300
Step-by-step explanation:
25%-----75 studens
100%-----x students
x=100×75/25= 300
The correct answer is the 2nd one
Answer:
IJ = 34
Step-by-step explanation:
Since HK = JK, then IK is a perpendicular bisector and Δ is isosceles, then
IJ = HI , that is
2s = s + 17 ( subtract s from both sides )
s = 17
Then
IJ = 2s = 2 × 17 = 34
Answer:
Mean and IQR
Step-by-step explanation:
The measure of centre gives the central or the measure which gives the best mid term of a distribution. Based in the details of the box plot, the median is the value which divides the box in the box plot.
For company A:
Range = 25 to 80 with a median value at 30 ; this means the median does not give a good centre measure of the distribution ad it is very close to the minimum value. This goes for the Company B plot too; with values ranging from (35 to 90) and the median designated at 40.
Hence, the mean will be the best measure of centre rather Than the median in this case.
For the variability, the interquartile range would best suit the distribution. With the lower quartile and upper quartile both having reasonable width to the minimum and maximum value of the distribution.
