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3 years ago

Solve for x: -4x – 12 > 36 A. x > -12 B. x > 12 C. x < -12 D. x < 12

Mathematics

2 answers:

Nataliya [291]3 years ago

4 0

Answer: x < -12

Step-by-step explanation:

-4x – 12 > 36

4x > 36+ 12

-4 > 48

x < -48/4

x < -12

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)

- Cutiepatutie ☺️❀❤

Mariana [72]3 years ago

4 0

Answer:

A. x > -12

Step-by-step explanation:

-4x – 12 > 36 add 12 to both sides of inequality

-4x > 48 divide both sides by 4

-x > 12 multiply it by -1

-12 < x and/or x > -12

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Hello! This is my first question ever. I am in AP Calculus and am working on a redo. I know the correct answer but don't know ho

Kipish [7]

Since $\Delta x=\dfrac{b-a}n$ , and you have a corresponding term in the given Riemann sum of $\dfrac5n$ , you know the integral is being taken over an interval of length 5, so you can omit the second choice.

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2 years ago

The length of a rectangle is 2 ft longer than its width.

notsponge [240]

If the length is 2ft longer than it’s width
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X+2+X=40
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6 0

3 years ago

What is the area of the triangle shown below?<br> 14

Sveta_85 [38]

Answer:

Excuse me but they is nothing shown below!

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5 0

3 years ago

In 1970, a farmer using a two-row combine with a corn head could easily harvest 0.75 ha (1.85 acres) per hour and a typical corn

Anastaziya [24]

Answer:

The value is $w = 6.7 \%$

Step-by-step explanation:

Generally the productivity rate is mathematically represented as

$P_r = K * Z$

Here K is the ha the farmer could harvest in an hour and Z is a typical yield of corn in kg/ha

Now considering 1970

The productivity rate is

$P_r = 0.75 *5000$

=> $P_r = 3750 \ kg/h$

Now considering 1940

The productivity rate is given as $P_R = 250 \ kg/h$

Generally the productivity ratio is mathematically ration is mathematically represented as

$w = \frac{P_R}{P_r} * 100$

=> $w = \frac{250}{3750} * 100$

=> $w = 6.7 \%$

5 0

3 years ago

Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0

3 years ago