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otez555 [7]
3 years ago
14

For a large batch of cupcakes the robots use 1/5 of gallon of milk. they pour it into 2 separate measuring cups each the same si

ze. how much milk goes into each measuring cup?
Mathematics
1 answer:
vodomira [7]3 years ago
6 0
<span>1/10 milk goes into each cup because 1/5 x 2 is 2/10 and 2/10 divided by 2 is 1/10 and that is your answer....Hope this helps!!!</span>
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Two bottles are selected at random, without replacement from a drawer containing 2 bottles of coke, 3 bottles of fanta and 4 bot
AVprozaik [17]

To find : outcomes for choosing 2 bottles (without replacement) from 3 various soft drink bottles in different numbers - coke , fanta , sprite

There can be total 2 x 3 , ie = 6 outcomes in this case.

Like two alphabets from A,B,C can be chosen without replacement in following 6 cases - A B  & B A , A C & C A , B C & C B

Similarly for Coke , Fanta , Sprite case ; total <u>outcomes</u><u> </u>are :-

  • Coke, Fanta
  • Fanta, Coke
  • Coke, Sprite
  • Sprite , Coke
  • Fanta , Sprite
  • Sprite , Fanta

For more information, refer brainly.com/question/23489473?referrer=searchResults

5 0
2 years ago
120 is what percent of 200
fredd [130]
The answer is 60% 
60% of 100 is 60
60% of 200 is 120
7 0
3 years ago
Read 2 more answers
Una lancha que viaja a 10 m/s pasa por debajo de un puente 3 segundos después que ha pasado un bote que viaja a 7 m/s, ¿después
ExtremeBDS [4]

Answer:

La lancha y el bote se encontrarán a 70 metros de distancia del puente.

Step-by-step explanation:

Sea el punto debajo del puente el punto de referencia y que ambas lanchas se desplazan a velocidad a continuación, las ecuaciones cinemáticas para cada embarcación son presentadas a continuación:

Bote a 7 metros por segundo

x_{A} = x_{o}+v_{A}\cdot t (Ec. 1)

Lancha a 10 metros por segundo

x_{B} = x_{o}+v_{B}\cdot (t-3\,s) (Ec. 2)

Donde:

x_{o} - Posición debajo del puente, medido en metros.

x_{A}, x_{B} - Posición final de cada embarcación, medido en metros.

v_{A}, v_{B} - Velocidad de cada embarcación, medida en metros por segundo.

t - Tiempo, medido en segundos.

Para determinar la posición en la que ambas embarcaciones se encuentran, se debe determinar el instante en que ocurre a partir de la siguiente condición: x_{A} = x_{B}

Igualando (Ec. 1) y (Ec. 2) se tiene que:

v_{A}\cdot t = v_{B}\cdot (t-3\,s)

Ahora despejamos el tiempo:

3\cdot v_{B} = (v_{B}-v_{A})\cdot t

t = \frac{3\cdot v_{B}}{v_{B}-v_{A}}

Si sabemos que v_{B} = 10\,\frac{m}{s} y v_{A} = 7\,\frac{m}{s}, entonces:

t = \frac{3\cdot \left(10\,\frac{m}{s} \right)}{10\,\frac{m}{s}-7\,\frac{m}{s}}

t = 10\,s

Ahora, la posición de encuentro es: (x_{o} = 0\,m, v_{A} = 7\,\frac{m}{s} y t = 10\,s)

x_{A} = 0\,m + \left(7\,\frac{m}{s} \right)\cdot (10\,s)

x_{A} = 70\,m

La lancha y el bote se encontrarán a 70 metros de distancia del puente.

6 0
3 years ago
If (x + 2) is a factor of x3 − 6x2 + kx + 10, k =
mafiozo [28]
Hello:
let : f(x) = <span>x3 − 6x2 + kx + 10
</span><span>If (x + 2) is a factor of x3 − 6x2 + kx + 10  : f(-2) = 0
(-2)^3-6(-2)² +k(-2)+10=0
-8 -24-2k +10 = 0
-2k =8+24-10
-2k = 22
k = -11</span>
7 0
3 years ago
Which option correctly represents the graph of f(x) = 2x2 -3 and describes
Naya [18.7K]

Answer:

even

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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