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lys-0071 [83]
3 years ago
13

What effect does "a" have on the parent function y=1/x

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0
Y=1/x is a reciprocal function & its shape is a special hyperbola with one branch located in the 1st Quadrant and the second in the 3dr Quadrant and both are symmetric about the origin O.
If a> 1 → y=a/x  and the 2 branches are equally stretched upward & downward
about the center O.
If  0 < a < 1→y =a/x, the 2 branches are equally stretched downward and upward about the center O.
If a<0, then the 2 legs are in the 2nd and 4th Quadrant respectively

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Simplified: 2x+ 7y + 12
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X=7

Step-by-step explanation:

7*15=105 7-2=5 5*25=125 125+105=230

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Felix earns $450 per week plus 3% of sales over $4800. Felix’s sales are $53000. How much does Felix earn?Felix earns $450 per w
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Answer:

<em>Felix earns total $594 per week.</em>

Step-by-step explanation:

Felix’s sales are $53000.

So, <u>the amount of sales over $4800 will be</u>:  \$53000-\$4800= \$48200

Felix earns $450 per week and additional 3% of sales over $4800.

So, his additional income = (\$4800\times 0.03)=\$144

Thus, Felix's total income will be:  (\$450+\$144)=\$594

3 0
4 years ago
Hayden's rectangular container has a height of 6ft and a base area of 72 square feet. Find the volume of water it would take to
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432ft^2

Step-by-step explanation:

7 0
3 years ago
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
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