Answer:
100 Candy Bars
Step-by-step explanation:
Hey!
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Ayden wants to sell a total of $150 worth of candy bars for his school fundraiser. Each candy bar costs $1.50. How many candy bars will he have to sell in order to meet his goal?
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We can create an algebraic Equation to solve this.
<u>- We know that Each Candy Bar costs $1.50.</u>
<u>-We multiply the Amount of Candy Bars with the price. </u>
<u>-We know the profit should be $150</u>
⇒ 1.50x = 150
-<u>Divide</u> by 1.50 on both sides
⇒ 1.50x/1.50 = 150/1.50
-<u>Simplify</u>
⇒ x = 100
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<em>Hope I Helped, Feel free to ask any questions to clarify :)
</em>
<em>
Have a great day!
</em>
<em>
More Love, More Peace, Less Hate.
</em>
<em> -Aadi x</em>
Answer:
the answer is b when we have two positives it makes a negitive therefore its b
Step-by-step explanation:
Using product rule;
f(x)=(1+6x²)(x-x²)
f'(x)=(12x)(x-x²) + (1-2x)(1+6x²) = 12x² -12x³ +1 +6x² -2x -12x³ = -24x³ +18x² -2x +1
Solving the bracket first;
f(x)=(1+6x²)(x-x²) = x -x² +6x³ -6x^4
f'(x)= 1 -2x +18x² -24x³ = -24x³ +18x² -2x +1
IT DOES NOT MATTER YOU WILL NOT BE ABLE TO SOLVE THIS QUESTION
YOU WOULD GET 5x = 2 + 3x^2 AND YOU WOULD STILL NOT BE ABLE TO SOLVE YOU COULD GET 3x^2 = 2 + 5x AND YOU COULD NOT SOLVE.
THE REASON WHY IS BECAUSE YOU HAVE TO HAVE THE SAME X TO ADD THEM OR MINUS THEM< WHICH IN THIS CASE ONE IS REGULAR BUT THE OTHER IS SQUARED. AND ALSO THE TWO NEEDS SOMEONE TO GO WITH< BUT THE IS ONLY ONE OF HIS TYPE SO HE CAN'T.
WELCOME :/
