PLEASE HELP!!!!!!

Mathematics

2 answers:

Nana76 [90]4 years ago

8 0

Answer:

Step-by-step explanation:

Let∠CBA,∠BAC and ∠BCA be the interior angles of the triangle ABC and Suppose that m || CB as m is the straight line, therefore using the straight line property, we have

∠CAY+∠CAB+∠BAX=180° (1)

Since, m is parallel to BC and AB is transversal, thus

∠BAX=∠CBA(Alternate interior angles of parallel lines cut by a transversal are congruent)

and ∠CAY=∠BCA(Alternate interior angles of parallel lines cut by a transversal are congruent.)

Now, substituting the values of ∠BAX and ∠CAY in equation (1), we have

∠CBA + ∠BAC + ∠BCA = 180°.

Hence, the sum of the measures of the interior angles of a triangle is 180°.

Inessa05 [86]4 years ago

6 0

You can use the Pythagorean theorem for this. A² + B² = C².

You can use this picture to get the proof.

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What is the result of isolating x2 in the equation below?(x + 1)2 + ( -8)2 =9A. x2 = -y2 - 2x +16y - 56B. x2 = y2 +2x+16y +56C.

Anit [1.1K]

The expression we have is:

$(x+1)^2+(y-8)^2=9$

Step 1. Use the binomial square formula:

$(a+b)=a^2+2ab+b^2$

Applying this formula to the first binomial squared:

$x^2+2x+1+(y-8)^2=9$

Step 2. Apply the formula for the square of a binomial to the second binomial:

$x^2+2x+1+y^2+2(y)(-8)+(-8)^2^{}=9$

In this case, we have some operations to solve before we move on to isolating x. So we solve the operations:

$x^2+2x+1+y^2-16y+64^{}=9$

Step 3. Move the terms that are not x squared to the right side of the expression. Remember that when we move one term from one side of the equation to the other, the term must change its sign. We get the following: