The polygons in each pair are similar. Find the missing side length

What’s the range of these temperatures -15, -6, 22, 10, -11

Nadya [2.5K]

range = largest - smallest

= 22 - (-15)

= 22 + 15

= 37

6 0

3 years ago

A circle is centered at J(3, 3) and has a radius of 12.

stealth61 [152]

Answer:

$(-6,\, -5)$ is outside the circle of radius of $12$ centered at $(3,\, 3)$ .

Step-by-step explanation:

Let $J$ and $r$ denote the center and the radius of this circle, respectively. Let $F$ be a point in the plane.

Let $d(J,\, F)$ denote the Euclidean distance between point $J$ and point $F$ .

In other words, if $J$ is at $(x_j,\, y_j)$ while $F$ is at $(x_f,\, y_f)$ , then $\displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}$ .

Point $F$ would be inside this circle if $d(J,\, F) < r$ . (In other words, the distance between $F\!$ and the center of this circle is smaller than the radius of this circle.)

Point $F$ would be on this circle if $d(J,\, F) = r$ . (In other words, the distance between $F\!$ and the center of this circle is exactly equal to the radius of this circle.)

Point $F$ would be outside this circle if $d(J,\, F) > r$ . (In other words, the distance between $F\!$ and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between $J$ and $F$ :

$\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145} \end{aligned}$ .

On the other hand, notice that the radius of this circle, $r = 12 = \sqrt{144}$ , is smaller than $d(J,\, F)$ . Therefore, point $F$ would be outside this circle.

5 0

3 years ago

Denzel and three friends go to the movies. each person buys a movie ticket for $8, a snack for $4, and a drink for $2. which num

swat32

8(4) + 4(4) + 4(2)
32 + 16 + 8

^^ Either one of these two expressions can be written down and they'd both be right.

6 0

3 years ago

find the value of x of given figure and solve this question step by step plzz help question number D

Alinara [238K]

Answer:

x=15 cm

Step-by-step explanation:

The two triangles in the diagram are:

ABC and BDC

First we have to find the third side (hypotenuse) of BDC so that we can use it to find the value of x.

Hypotenuse is the largest side of a triangle which is usually in front of the right angle.

So in BDC

$Base = BD =10cm\\Hypotenuse = BC = ?\\Perpendicular = CD = 2\sqrt{11}cm$

Applying Pythagoras theorem:

$(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2\\BC^2 = BD^2 + CD^2\\BC^2 = (10)^2 + (2\sqrt{11})^2\\BC^2 = 100+(2^2 * 11)\\BC^2 = 100+(4*11)\\BC^2 = 100+44\\BC^2 = 144\\\sqrt{BC^2} = \sqrt{144}\\BC = 12cm$

Solving for triangle ABC

$Base = BC = 12 cm\\Perpendicular = AB = 9 cm\\Hypotenuse = AC = x\\$

Applying Pythagoras theorem

$AC^2 = BC^2+AB^2\\x^2 = (12)^2 + (9)^2\\x^2 = 144+81\\x^2 = 225\\\sqrt{x^2} = \sqrt{225}\\x = 15cm$

Hence,

x=15 cm

8 0

3 years ago

In ΔOPQ, PQ = 17, QO = 9, and OP = 15. Which statement about the angles of ΔOPQ must be true?

77julia77 [94]

Answer:

All angles are different.

Internal angles can be acute, obtuse, or right angle.

The smallest side is opposite to the smallest angle and the longer side is opposite to the larger angle.

Step-by-step explanation:

Given - In ΔOPQ, PQ = 17, QO = 9, and OP = 15.

To find - Which statement about the angles of ΔOPQ must be true?

Proof -

As given,

In ΔOPQ, PQ = 17, QO = 9, and OP = 15.

As all the sides of the given triangle is different, So the given triangle is a Scalene triangle.

Now,

We know that , In Scalene triangle -

All sides are different.

All angles are different.

Internal angles can be acute, obtuse, or right angle.

The smallest side is opposite to the smallest angle and the longer side is opposite to the larger angle.

6 0

3 years ago