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3 years ago

Help me with 8 - 11 please

Mathematics

1 answer:

Alexus [3.1K]3 years ago

7 0

Answer:(question8 x=28),(question9 x=18),(question10 x=22),(question11 x=45)

Step-by-step explanation:

Question 8

2x+1+33=90

2x+34=90

2x=90-34

2x=56

Divide both sides by 2

x=56/2

x=28

Question 9

3x+11+25+90=180

3x+126=180

3x=180-126

3x=54

Divide both sides by 3

x=54 ➗ 3

x=18

Question 10

5x+12=6x-10

Collect like terms

6x-5x=12+10

x=22

Question 11

45+3x=180

3x=180-45

3x=135

Divide both sides by 3

x=135 ➗ 3

x=45

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3 years ago

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Answer:

$\boxed {\boxed {\sf x=2}}$

Step-by-step explanation:

The axis of symmetry can be calculated using the formula:

$x=\frac{-b}{2a}$

First we must determine a and b from the quadratic: $-x^2+4x-8$ . This is in standard form, with the highest power first in descending order.

Standard form is also: $ax^2+bx+c$

If we compare this to the quadratic given, we can conclude that:

$a= -1 \\b= 4 \\c= -8$

Substitute the values for a and b into the formula.

$x= \frac{-(4)}{2(-1)}$

Multiply in the denominator.

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Divide.

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This can also be determined from the graph. It is the x-coordinate of the vertex or the maximum/minimum. It divides the quadratic into 2 symmetrical halves.

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