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Strike441 [17]
3 years ago
6

Suppose y varies directly with x. if y=7 when x=2, find y when x=3

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0
7/2=y/3

21=2y

Y=21/2

Hope this helps!
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Write an expression to show k less than 3.5
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Answer: k < 3.5
explanation: < means less than and > means more than and = means equal to so k < (less than) 3.5
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A factory whistle blows every 30 minutes. The clock tower chimes every 15 minutes. If they both sounded at 1:00 p.M.,at what tim
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Answer:

1.30 p.M.

Step-by-step explanation:

The factory whistle blowed at 1:00 p.M, and it blows every 30 minutes, so it will blow again at 1:30 p.M.

The clock tower chimed at 1.00 p.M., and it chimes every 15 minutes, so it will chime again at 1:15 p.M, and after that, it will chime again at 1:30 p.M.

So, you will hear them both at the same time at 1:30 p.M.

We can also solve this problem using LCM:

the least commom multiple between 15 and 30 is 30, so we just need to sum 30 to the inicial time (1:00 p.M.), so the time they will "find each other" again is 1.30 p.M.

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3 years ago
Six more than five times a number (x) is at least twenty-one
I am Lyosha [343]
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Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

8 0
1 year ago
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