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MAVERICK [17]
3 years ago
5

X^2 – 5x + 6 < 0 what is the answer

Mathematics
1 answer:
Sophie [7]3 years ago
7 0

Answer:

step 1: x2−5x+6<0

step2: (×-2) (+-3) =0

answer would be: 2<x<3

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The nth term of a sequence is 3n2-1
maksim [4K]

Answer: The common number is 26.

Step-by-step explanation:

We know that the n-th term of a sequence is:

aₙ = 3*n^2 - 1

And the n-th term of another sequence is:

bₙ = 30 - n^2

Remember that in a sequence n is always an integer number.

We want to find a number that belongs to both sequences, then we want to find a pair of integers x and n, such that:

aₙ = bₓ

This is:

3*n^2 - 1 = 30 - x^2

Let's isolate one of the variables, i will isolate n.

3*n^2 = 30 - x^2 + 1 = 31 - x^2

n^2 = (31 - x^2)/3

n = √( (31 - x^2)/3)

Now we can try with different integer values of x, and see if n is also an integer.

if x = 1

n = √( (31 - 1^2)/3) = √10

We know that √10 is not an integer, so we need to try with another value of x.

if x = 2:

n = √( (31 - x^2)/3) = √(27/3) = √9 = 3

Then if we have x= 2, n is also an integer, n = 3.

Then we have:

a₃ = b₂

The common number between both sequences is:

a₃ = 3*(3)^2 - 1 = 26

b₂ = 30 - 2^2 = 26

6 0
4 years ago
Can anyone help me with number 5 ??
emmasim [6.3K]
72.5 weeks. if you subtract 1,000 from 2,450, you will have 1,450. now, divide this by 20. it is 72.5 weeks.
7 0
3 years ago
The hypotenuse of a right triangle is 89 meters long. One leg of the triangle is 39 meters long. What is the length of the other
Hitman42 [59]
A²+b²=c²
39²+b²=89²
1521+b²=7921
subtract 1521 from both sides
b²=6400
so then you square both sides
√6400
80
4 0
4 years ago
Help with maths please
LekaFEV [45]
maybe 8:02 maybe not surew
5 0
4 years ago
Read 2 more answers
Can someone help me with this?
Nimfa-mama [501]

Answer:

Kite x=1, y=7

Step-by-step explanation:

It is a kite.

The two lines on the bottom corners of the kite mean they have the same value.

X=1 so 3x+4

3 *1 +4=7

And: x+6

1+6=7.

X+4=1+4=5.

Y=7 so y-2

7-2=5.

Hope it helped you

6 0
3 years ago
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