<h2>
[A] Plane S contains points B and E.</h2>
False
As indicated in Figure A below, Plane S contains only point B (remarked in red). Point E (remarked in blue) lies on plane R.
<h2>
[B] The line containing points A and B lies entirely in plane T.</h2>
True
As indicated in Figure B below, the line containing points A and B lies entirely in plane T. That line has been remarked in red and it is obvious that lies on plane T.
<h2>
[C] Line v intersects lines x and y at the same point.</h2>
False
As indicated in Figure C below, line v intersects lines x and y, but line x in intersected at point B while line y (remarked in red) is intersected at point A (remarked in blue), and they are two different points, not the same.
<h2>
[D] Line z intersects plane S at point C.</h2>
True
As indicated in Figure D below, line z that has been remarked in yellow, intersects plane S at point C that has been remarked in blue.
<h2>
[E] Planes R and T intersect at line y.</h2>
True
As indicated in Figure E below, planes R and T intersect at line y. The line of intersection has been remarked in red.
All you have to do is divide 92 by 6 and you get your answer. The remainder is the spaces she'll have left
Answer:
The population when t = 3 is 10.
Step-by-step explanation:
Suppose a certain population satisfies the logistic equation given by

with P(0)=1. We need to find the population when t=3.
Using variable separable method we get

Integrate both sides.
.... (1)
Using partial fraction


Using these values the equation (1) can be written as


On simplification we get


We have P(0)=1
Substitute t=0 and P=1 in above equation.


The required equation is

Multiply both sides by 10.



Reciprocal it


The population when t = 3 is

Using calculator,

Therefore, the population when t = 3 is 10.
The chicken cost $1.57 per pound.
You figure this out by dividing the total amount of chicken 5.5lbs (5 1/2) by the cost per pound.
5.5 / 3.50 = 1.57
Answer:
Figure 3
Figure 1
Step-by-step explanation:
Figure 1 is the pre-image
The side length is 2. We multiply the side length by the scale factor.
2 * 4 = 8
The new figure will have a side length of 8. That will be Figure 3
Figure 2 is the pre-image
The side length is 4. We multiply the side length by the scale factor.
4 * 1/2 = 2
The new figure will have a side length of 2. That will be Figure 1