3 years ago

What is the perimeter, P, of a rectangle that has a length of x + 8 and a width of y-1?

Mathematics

1 answer:

Alenkinab [10]3 years ago

8 0

Answer:

Step-by-step explanation:

Perimeter = 2*(length +width)

P = 2*( x+8 + y-1)

P = 2*(x + y + 7)

P =2x + 2y + 17

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