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kondaur [170]
3 years ago
7

250 divided by 10 to the 2 nd power

Mathematics
2 answers:
laila [671]3 years ago
5 0
The answer to your problem is 2.5.
o-na [289]3 years ago
5 0
The first possibility: the entire expression is squared -
(250/10)^2
25^2
625

The second possibility: the 10 in the denominator is squared -
250/(10^2)
250/100
5/2

Answer:
Either 625 or 5/2, depending on the question.

Hope this helps!
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Convert 4/12 into a decimal round to the nearest tenths place
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Answer:

0.3

Step-by-step explanation:

4 divided by 12 is .333333333… and the tenths place is right after the decimal point. ex: 5.67 with 6 being in the tenths place. since 3 can’t be rounded upto add onto the tenths place, it stays as .3.

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2 years ago
Does the absolute value graph below flip or not flip? F(x)=2|x-9|+3
deff fn [24]

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Option C, the graph does not flip because 2 is positive

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3 years ago
What is the measure of the missing angle?
Yakvenalex [24]

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140°

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3 years ago
Yuki has saved £100 and spends £22 on a present. Rosetta has saved £140 and spends £28 on a present. What percentage has each gi
grigory [225]

Answer:

yuki has spent 22 percent , Rosetta spent 20 percent

step by step explanation:

1) if £100=100percent

then £22=x percent

x=(22×100)/100=22 percent

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6 0
3 years ago
Each pound of food C contains 6 ounces of ingredient P and 3 ounces of ingredient Q. Each pound of food D contains 4.5 ounces of
GuDViN [60]
So hmm the food C = 6p + 3q  and the food D = 4.5p + 1.5q

now, if we check how much is the ratios of C/D for each component, then, mixture M = 144p + 60q, must contain the same ratio for each "p" and "q" component

\bf \textit{ratio of "p"}\implies \cfrac{6}{4.5}\implies \cfrac{4}{3}
\\\\\\
\textit{ratio of "q"}\implies \cfrac{3}{1.5}\implies \cfrac{2}{1}

so, if we divide the 144p by 4+3, or 7 even pieces, 4 must belong to food C and 3 to food D, retaining the ratio of 4/3

and we do the same for 60q, we divide it in 2+1 or 3 even pieces, but that one is very clear, 2 must belong to food C and 1 to food D, 60/3 is clear ends up with a ratio of 40 and 20

now the "p" part... ends up as \bf \cfrac{144}{7}\cdot 4\qquad and\qquad \cfrac{144}{7}\cdot 3\implies \cfrac{576}{7}\qquad and\qquad \cfrac{432}{7}

that's what I see it, as the ratio of 4/3 and 2/1 being retained in the mixture M
7 0
3 years ago
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