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Ronch [10]
3 years ago
5

If the first and third of three consecutive even integers are added, the result is 22 less than three times the second integer.

Find the integer.
Mathematics
1 answer:
lord [1]3 years ago
4 0
3 consecutive even integers....x, x + 2, x + 4

x + x + 4 = 3(x + 2) - 22
2x + 4 = 3x + 6 - 22
2x + 4 = 3x - 16
16 + 4 = 3x - 2x
20 = x

x + 2 = 20 + 2 = 22
x + 4 = 20 + 4 = 24

ur 3 integers are : 20,22,24

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In a popular online role playing game, players can create detailed designs for their character's "costumes," or appearance. Oliv
sveticcg [70]

Answer:

There is a 54.328% probability that the next person will purchase no more than one costume.

Step-by-step explanation:

Since in a popular online role playing game, players can create detailed designs for their character's "costumes," or appearance, and Olivia sets up a website where players can buy and sell these costumes online, and information about the number of people who visited. the website and the number of costumes purchased in a single day states that 144 visitors purchased no costume, 182 visitors purchased exactly one costume, and 9 visitors purchased more than one costume, to determine, based on these results, the probability that the next person will purchase no more than one costume as a decimal to the nearest hundredth, the following calculation must be performed:

144 + 182 + 9 = 335

335 = 100

182 = X

182 x 100/335 = X

18,200 / 335 = X

54,328 = X

Therefore, there is a 54.328% probability that the next person will purchase no more than one costume.

3 0
3 years ago
Researchers are interested if a school breakfast program leads to taller children. Assume that the population of all 5 year-old
DedPeter [7]

Answer:

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=39 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1 represent the population standard deviation

n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

And replacing we got:

ME= 1.96 *\frac{1}{\sqrt{25}}= 0.392

Now we have everything in order to replace into formula (1):

39-1.96\frac{1}{\sqrt{25}}=38.608    

39+1.96\frac{1}{\sqrt{25}}=39.392    

So on this case the 95% confidence interval would be given by (38.608;39.392)    

7 0
3 years ago
9 more than a number is 58. write and solve an equation to determine the number (writing the equation is required)
Stels [109]

58 - 9 = 49
5 0
4 years ago
Karnataka cuts a length of ribbons into 4 equal pieces, each 1 1/4 feet long how long was the ribbon?
nasty-shy [4]
4 *  1 1/4 = 5 
Hope I helped ! :-)
7 0
4 years ago
Read 2 more answers
What is the fourth term in the expansion of (x + 2y)^8?
Hatshy [7]
Base on my calculation and the simplification of the form and finding its 4th power of the x+2y, i came up with a solution and finally found an answer of B. 448x^5y^3, I hope i answer your questions directly and please feel free to ask for more and ask for clarifications
4 0
4 years ago
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